I have a script like this--
#!/bin/ksh
echo "To pad a 0 before digits from 1-9"
for i in $*
do
echo $i | sed 's//'0'/g'
done
I run this script as
ksh name 1 2 23 34
The output should be
01 02 23 34
Help me in modifying this script.
Thanks
Namish (2 Replies)
Folks,
Is there a simple way to replace one digit by two digit using sed.
Example,
mydigit1918_2006_8_8_lag1.csv should be
mydigit1918_2006_08_08_lag01.csv.
I tried this way, but doesn't work.
echo mydigit1989_2006_8_8_lag1.csv|sed 's/]/0]/'
Thank you, (5 Replies)
Hi All,
How can i convert a number 24 to 0024
In the same way how can i convert 123 to 0123?
All this has to be done inside a script
Thanks in advance
JS (6 Replies)
hi all,
how do i format the date command so it displays day and month in single digits i.e 8 instead of 08 ??
am using the command (in a ksh) : date +%D
output i get is 10/08/08
thanks in advance. (5 Replies)
hi all,
how do i get the month in single digit in ksh script ?? my command for date is :
/usr/bin/date +%Om/%Oe/%y | sed 's/ //g'
which returns "01/16/09" but i need the output to be "1/16/09" i.e the month without leading zero.
thanks in advance. (2 Replies)
I have a var storing date
var=`date`
Now the date is returned as
Mon Feb 2 00:25:48 PST 2009
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pattern file pattern.txt
pattern num
bala 2
raja 3
muthu 4
File Name: chennai.dat
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I'm trying to acheive the following, I have a dat file in which i have several addresses, If the address starts with a single digit then i have to delete the line,
if it starts with 2 or more digits then i have to keep the line
Here is a sample of my file:
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I have a file which keeps count based on completion of a certain activity. I am using the following grep command to return a '1' in case the count is zero
grep -ic "0" abc_count.txt
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