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Full Discussion: awk with fields select?
Top Forums Shell Programming and Scripting awk with fields select? Post 302601836 by sabercats on Friday 24th of February 2012 01:39:59 PM
Old 02-24-2012
Hi Chubler_XL,
I replaced nowtime= current time in epoch
Code:
awk -F\| '
  $7 == "In Use" && not ($8 in U) {
      U[$8]=$10;
       nowtime=$(date +%s)
      A[$8]=$nowtime;
     
  }
  $7 == "Available" {A[$8]=$10}
  END {for(id in U)
print U[id] "||||||" (A[id]=="$nowtime"?"Available":"In Use") "|" id "||" A[id] }' record.txt

--> i got the result
Unmatched .

Do you know what was wrong? Thanks.
 

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GETDATE(1)							   User Commands							GETDATE(1)

NAME
getdate - AME SYNOPSIS
[-dv][-n dec][-f format] [ra dec sys] itype2otype [date and/or time] DESCRIPTION
Convert date and time between various formats [-dv][-n dec][-f format] itype2otype @file itype: nfd=ISOFITS fd=FITS, dt=yyyy.mmdd, hr=hh:mm:ss, deg=dd:mm:ss jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD ep=epoch, epj=Julian epoch, epb=Besselian epoch lt=local time, ut=UT, ts=seconds since 1950-01-01 now=current time, ang=fractional degrees otype: fd=FITS, dt=yyyy.mmdd, jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD hr=hh:mm:ss, deg=dd:mm:ss, ang=fractional degrees ep=epoch, epj=Julian epoch, epb=Besselian epoch ts=seconds since 1950-01-01, tsu=Unix sec, tsi=IRAF sec gst=Greenwich Sidereal Time, lst=Local Sidereal Time @file: First one or two columns are in itype format ra dec sys: Need for Heliocentric conversions -a: Append date to input file, if there is one -d: Print date without time -e: Print output as ET/TDT/TT converting from UT -f: Format for output number (C printf) -h hours: Longitude in hours, west positive -l degrees: Longitude in degrees, west positive -n: Number of decimal places in sec, epoch, JD -t: Print time without date -v: Verbose getdate 3.8.4 June 2012 GETDATE(1)
All times are GMT -4. The time now is 09:15 PM.
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