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Error:--test: argument expected--Even though i give an argument.
Post 302600053 by harsha85 on Monday 20th of February 2012 02:41:55 AM
02-20-2012
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+
test.sh: test: argument expected
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echo elseeee
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why does it show this error? Clearly from debug mode, the argument is passed. I also tried if
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LEARN ABOUT PHP
apc_cas
APC_CAS(3) 1 APC_CAS(3) apc_cas - Updates an old value with a new value SYNOPSIS
bool apc_cas (string $key, int $old, int $new) DESCRIPTION
apc_cas(3) updates an already existing integer value if the $old parameter matches the currently stored value with the value of the $new parameter. PARAMETERS
o $key - The key of the value being updated. o $old - The old value (the value currently stored). o $new - The new value to update to. RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 apc_cas(3) example <?php apc_store('foobar', 2); echo '$foobar = 2', PHP_EOL; echo '$foobar == 1 ? 2 : 1 = ', (apc_cas('foobar', 1, 2) ? 'ok' : 'fail'), PHP_EOL; echo '$foobar == 2 ? 1 : 2 = ', (apc_cas('foobar', 2, 1) ? 'ok' : 'fail'), PHP_EOL; echo '$foobar = ', apc_fetch('foobar'), PHP_EOL; echo '$f__bar == 1 ? 2 : 1 = ', (apc_cas('f__bar', 1, 2) ? 'ok' : 'fail'), PHP_EOL; apc_store('perfection', 'xyz'); echo '$perfection == 2 ? 1 : 2 = ', (apc_cas('perfection', 2, 1) ? 'ok' : 'epic fail'), PHP_EOL; echo '$foobar = ', apc_fetch('foobar'), PHP_EOL; ?> The above example will output something similar to: $foobar = 2 $foobar == 1 ? 2 : 1 = fail $foobar == 2 ? 1 : 2 = ok $foobar = 1 $f__bar == 1 ? 2 : 1 = fail $perfection == 2 ? 1 : 2 = epic fail $foobar = 1 SEE ALSO
apc_dec(3), apc_store(3). PHP Documentation Group APC_CAS(3)