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Top Forums Shell Programming and Scripting Error while reading from a file in shell script Post 302598902 by Corona688 on Wednesday 15th of February 2012 04:43:01 PM
Old 02-15-2012
You don't use $ when assigning a variable.

Code:
username=$(awk '{print "youare" $line "bond"}')

You don't need awk for this, however! Never use external utilities for things you can do with builtins, especially when processing individual lines. Running awk 9,000 times for 9,000 lines is like making 9,000 phonecalls to say 9,000 words.

You don't need another variable for this, either. I'm guessing awk got resorted to because "youare$linebond" tries to use the variable $linebond and not $line. You can surround the variable with {} brackets to prevent this.

Code:
while read line
do
        echo $line
        echo "youare${line}bond"
done</home/gunner/users.txt

 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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