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Full Discussion: Treating string as date ?
Top Forums Shell Programming and Scripting Treating string as date ? Post 302598744 by SFNYC on Wednesday 15th of February 2012 10:19:17 AM
Old 02-15-2012
You could parse the date like this

Code:
$ cat compare_dates.ksh
#!/bin/ksh

USERDATE="2/15/2012"
IFS=/
set -- $USERDATE
typeset -Z2 MONTH=$1
typeset -Z2 DAY=$2
YEAR=$3
MYDATE="$YEAR$MONTH$DAY"
echo $MYDATE

TODAY=$(date +%Y%m%d)

if [ $TODAY -eq $MYDATE ]; then
     echo "We have a match!"
fi

exit 0

$ ./compare_dates.ksh
20120215
We have a match!

 

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DATETIMEINTERFACE.FORMAT(3)						 1					       DATETIMEINTERFACE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeInterface.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEINTERFACE.FORMAT(3)
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