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Top Forums Shell Programming and Scripting how to use "cut" or "awk" or "sed" to remove a string Post 302597801 by pandeesh on Sunday 12th of February 2012 08:57:56 AM
Old 02-12-2012
Hi

can you please explain the below part:
Code:
awk -F'[/"]*'

Thanks

---------- Post updated at 07:27 PM ---------- Previous update was at 07:05 PM ----------

Pure bash solution for interest:
Code:
pandeeswaran@ubuntu:~$ while read line; do line1=`echo $line|cut -d/ -f1,3|tr -d \"/`; echo $line1; done < log
[Sun Feb 12 10:36:20 2012] abc
[Sun Feb 12 10:36:20 2012] abc
[Sun Feb 12 10:36:20 2012] xyz
[Sun Feb 12 10:36:21 2012] xyz
[Sun Feb 12 10:36:21 2012] xyz

 

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CONVDATE(1)						      General Commands Manual						       CONVDATE(1)

NAME
convdate - convert time/date strings and numbers SYNOPSIS
convdate [ -c ] [ -n ] [ -s ] arg... DESCRIPTION
Convdate translate the date/time strings specified as arguments on its command line, outputting the results one to a line. OPTIONS
-c If the ``-c'' flag is used, then each argument is taken to be a time_t and is output in ctime format. -n If the ``-n'' flag is used, then each argument is taken as a date string to be parsed by parsedate(3) and is output as a time_t; see time(2). -s If the ``-s'' flag is used, then each argument is taken as a date string to be parsed by parsedate(3) and is output as a string for- matted by ctime(3). This is the default. EXAMPLES
% convdate 'feb 10 10am' Sun Feb 10 10:00:00 1991 % convdate 12pm 5/4/90 Fri Dec 13 00:00:00 1991 Fri May 4 00:00:00 1990 % convdate -n 'feb 10 10am' '12pm 5/4/90' 666198000 641880000 % convdate -c 666198000 Sun Feb 10 10:00:00 1991 HISTORY
Written by Rich $alz <rsalz@uunet.uu.net>. This is revision 1.2, dated 1998/05/20. SEE ALSO
parsedate(3). CONVDATE(1)
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