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Full Discussion: c programming system call
Top Forums Programming c programming system call Post 302597273 by agama on Thursday 9th of February 2012 09:41:24 PM
Old 02-09-2012
It's very difficult to guess what might be your problem without seeing more of the code. Posting at least the complete function that your chmod() call is in would provide some clue as to what is going on.

The error you are getting seems to be suggesting that the chmod() statement is being interpreted as the declaration of a function, rather than a statement in the body of your programme.
 

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explain_chmod_or_die(3) 				     Library Functions Manual					   explain_chmod_or_die(3)

NAME
explain_chmod_or_die - change permissions of a file and report errors SYNOPSIS
#include <libexplain/chmod.h> void explain_chmod_or_die(const char *pathname, int mode); DESCRIPTION
The explain_chmod_or_die function is used to call the chmod(2) system call. On failure an explanation wiil be printed to stderr, obtained from explain_chmod(3), and the the process terminates by calling exit(EXIT_FAILURE). This function is intended to be used in a fashion similar to the following example: explain_chmod_or_die(pathname, mode); pathname The pathname, exactly as to be passed to the chmod(2) system call. mode The mode, exactly as to be passed to the chmod(2) system call. Returns: This function only returns on success. On failure, prints an explanation and exit(EXIT_FAILURE)s. COPYRIGHT
libexplain version 0.52 Copyright (C) 2008 Peter Miller AUTHOR
Written by Peter Miller <pmiller@opensource.org.au> explain_chmod_or_die(3)
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