Sponsored Content
Top Forums Shell Programming and Scripting How to grep a portion of line Post 302596963 by balajesuri on Wednesday 8th of February 2012 08:11:24 PM
Old 02-08-2012
1. Your requirements keep changing over the posts.
2. One way to achieve requirement mentioned in post #5 is to write a script that will keep scanning the file until a certain condition is met.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

erasing portion of line with sed

hi, I'm trying to use sed to erase everything, and including the ending parenthesis. For example: input: blah blah blah (12355)this is what i want. output: this is what i want. how would i do this? i found an example online that does the opposite: sed \"s|test.*||g\" file1 > file2"; ... (5 Replies)
Discussion started by: gammaman
5 Replies

2. UNIX for Dummies Questions & Answers

erasing portion of line with sed (only once)

hi, I'm trying to use sed to erase everything, up to the first parenthesis. for example: input: blah blah blah (aldj) test (dafs) test test. output: (aldj) test (dafs) test test. how would i do this? I was fooling around with the parenthesis, and i only got it to apply on all parenthesis.... (1 Reply)
Discussion started by: gammaman
1 Replies

3. Shell Programming and Scripting

Delete a portion of a line using shell scripting

Hi all, I am new to awk programs.I have a file like this 1234567@2345||adcbdefhij: asgdfdasdfhhfd-asdfasd-dsfasdf |0.678|0.0|0.213 1234567@2345||adcbdefhij: ashhfd-asdfasd-dsfasdf |0.129|0.0|0.411 1234567@2345||adcbdefhij: asd-aasd-dasdf |0.223|0.0|0.276 I want to delete the text which... (3 Replies)
Discussion started by: Loy81
3 Replies

4. Shell Programming and Scripting

Print a portion of a line

Hi, I am facing a little problem... I have a line like this : asdcvashfasashXXXXxxxzxcadd:sdcashjqdasdsmgdkdaxdsnd; I want to print just a portion of line i.e starting from left 5 characters from ":" and upto ";" i.e. in this case it would be "xcadd:sdcashjqdasdsmgdkdaxdsnd;" The length of... (2 Replies)
Discussion started by: vanand420
2 Replies

5. Shell Programming and Scripting

Grep certain portion from the file

Dear Friends, Here I am with another difficulty. I have a flat file from which I wanna grep following pattern. - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Statement Date : Blah blah Blah blah Blah blah Blah blah... (1 Reply)
Discussion started by: anushree.a
1 Replies

6. UNIX for Advanced & Expert Users

Grep a portion of the log file

I want to grep a portion of the log file. grepping a particular pattern and including 10 lines before that and after that occurence. grep -n "SomeString Pattern" filename 10 lines before this occurence and 10 lines after that. Please help. Need the simple script not in awk or sed. (9 Replies)
Discussion started by: sainipardeep
9 Replies

7. Shell Programming and Scripting

Print portion line in SED

Hi, This is more a theoretical question, because I usually solved that with perl or even java, but I would like to know if it exists an easy way to do it with SED. Using regular expresions it's very easy to select an portion line. Does it exist an easy way for printing those portions in SED?... (1 Reply)
Discussion started by: islegmar
1 Replies

8. UNIX for Dummies Questions & Answers

Grab Portion of Output Text (sed, grep, awk?)

Alright, here's the deal. I'm running the following ruby script (output follows): >> /Users/name/bin/acweather.rb -z 54321 -o /Users/name/bin -c Clouds AND Sun 57/33 - Mostly sunny and cool I want to just grab the "57/33" portion, but that's it. I don't want any other portion of the line. I... (5 Replies)
Discussion started by: compulsiveguile
5 Replies

9. Shell Programming and Scripting

Shell to display portion of a line

Thanks a lot for the code and the explanation. Now my final requirement. I have uploaded 3 files as attachment. Please open the files in Editplus or any other text editor which keeps the formatting. GMDCOM.27936.log.txt------I want to pick only Process request from this file.(Please check... (9 Replies)
Discussion started by: ghosh_tanmoy
9 Replies

10. UNIX for Beginners Questions & Answers

How do I separate a portion of a file name to use grep on?

I'm trying to write a script that takes a file name in the form of Name_Num1_Num2.Extension and I want to separate the name portion and then use grep to see if that name part has any illegal characters in it. I already have my grep command written and it works, I'm not sure how to separate the... (5 Replies)
Discussion started by: steezuschrist96
5 Replies
CSREQ(1)						    BSD General Commands Manual 						  CSREQ(1)

NAME
csreq -- Expert tool for manipulating Code Signing Requirement data SYNOPSIS
csreq [-v] -r requirement-input -t csreq [-v] -r requirement-input -b outputfile DESCRIPTION
The csreq command manipulates Code Signing Requirement data. It reads one requirement from a file or command arguments, converts it into internal form, checks it, and then optionally outputs it in a different form. The options are as follows: -b path Requests that the requirement read be written in binary form to the path given. -r requirement-input Specifies the input requirement. See "specifying requirements" below. This is exactly the same format as is accepted by the -r and -R options of the codesign(1) command. -t Requests that the requirement read be written as text to standard output. -v Increases the verbosity of output. Multiple instances of -v produce increasing levels of commentary output. In the first synopsis form, csreq reads a Code Requirement and writes it to standard output as canonical source text. Note that with text input, this actually compiles the requirement into internal form and then converts it back to text, giving you the system's view of the requirement code. In the second synopsis form, csreq reads a Code Requirement and writes its binary representation to a file. This is the same form produced by the SecRequirementCopyData API, and is readily acceptable as input to Code Signing verification APIs. It can also be used as input to subse- quent invocations of csreq by passing the filename to the -r option. SPECIFYING REQUIREMENTS
The requirement argument (-r) can be given in various forms. A plain text argument is taken to be a path to a file containing the require- ment. This program will accept both binary files containing properly compiled requirements code, and source files that are automatically com- piled for use. An argument of "-" requests that the requirement(s) are read from standard input. Again, standard input can contain either binary form or text. Finally, an argument that begins with an equal sign "=" is taken as a literal requirements source text, and is compiled accordingly for use. EXAMPLES
To compile an explicit requirement program and write its binary form to file "output": csreq -r="identifier com.foo.test" -b output.csreq To display the requirement program embedded at offset 1234 of file "foo": tail -b 1234 foo | csreq -r- -t FILES
DIAGNOSTICS
The csreq program exits 0 on success or 1 on failure. Errors in arguments yield exit code 2. SEE ALSO
codesign(1) HISTORY
The csreq command first appeared in Mac OS 10.5.0 . BSD
June 1, 2006 BSD
All times are GMT -4. The time now is 05:00 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy