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Top Forums Shell Programming and Scripting Rename files that are inside zip file Post 302596593 by Ophiuchus on Tuesday 7th of February 2012 09:35:09 PM
Old 02-07-2012
Hi anchal_kare,

Thank for your reply.

I wasn't able to get the correct regex to use within sed to rename the files, but using that bash option "${fname#*_}" was the way I could do it unzipping first the file and then renaming each file inside the zip.

Thanks again.

Greetings
 

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ZIP_SOURCE_FILE(3)					     Library Functions Manual						ZIP_SOURCE_FILE(3)

NAME
zip_source_file - create data source from a file LIBRARY
libzip (-lzip) SYNOPSIS
struct zip_source * zip_source_file(struct zip *archive, const char *fname); "zip_uint64_t start" "zip_int64_t len" DESCRIPTION
The function zip_source_file creates a zip source from a file. zip_source_file opens fname and reads len bytes from offset start from it. If len is 0 or -1, the whole file (starting from start ) is used. The fie is opened and read when the data from the source is used, usually by zip_close. RETURN VALUES
Upon successful completion, the created source is returned. Otherwise, NULL is returned and the error code in archive is set to indicate the error. ERRORS
zip_source_file fails if: [ZIP_ER_INVAL] fname, start, or len are invalid. [ZIP_ER_MEMORY] Required memory could not be allocated. [ZIP_ER_OPEN] Opening fname failed. SEE ALSO
libzip(3), zip_add(3), zip_replace(3), zip_source_buffer(3), zip_source_filep(3), zip_source_free(3), zip_source_function(3), zip_source_zip(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH August 1, 2008 ZIP_SOURCE_FILE(3)
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