Is it csh or tcsh shell that you are using? From memory, for csh you use a \ in the path names instead of a / for tcsh. You appear to be escaping the wildcard *. You also need to put curly brackets around some of your path names that use a combination of variables. I didn't test your code but my edits for a tcsh script would be as follows:
Code:
#!/bin/tcsh
set directory1 = "/data/htdocs/field_photos/files/by_site"
echo $directory1
set station = "P101 P360"
set year = "2011 2012"
set month = "01 02 03 04 05 06 07 08 09 10 11 12"
foreach year($year)
wget -P $directory1 -nc ftp://brick.unavco.org/in/hodge/P101${year}*.jpg
wget -P $directory1 -nc ftp://brick.unavco.org/in/hodge/P360${year}*.jpg
end
foreach station($station)
foreach year($year)
foreach month($month)
echo ${directory1}/${station}${year}*.jpg ${directory1}/${station}/webcam/${year}/$month
chmod g+rw ${directory1}/${station}${year}${month}*.jpg
mv ${directory1}/${station}${year}${month}*.jpg ${directory1}/${station}/webcam/${year}/${month}
end
end
end
Hello, I am new at this forum so please bare with me on this.
Within a given directory, I have a list of files in which in each file, I would like to do a substitution. I would like to substitute the string mlcl to mll in each file using the foreach command. I dont quite get how to do that. If... (7 Replies)
Hi Guys,
I have a loop which uses a wildcard
i.e. foreach f (*)
but when I execute the tcsh file in unix then it gives me an error
->>>>>>>foreach: words not parenthesized<<<<<<<<<<-
Any help. (1 Reply)
In a foreach loop, is it possible for the loop to go through 2 arguments instead of one
i.e. instead of foreach i (do stuff for i), we have foreach i j(do stuff for i; do stuff for j)
I am working under BASH and TCSH shell environments
cheers (3 Replies)
Hi everyone
Does anyone know what is wrong with this script. i keep getting errors
foreach filename (`cat testing1`)
set string=$filename
set depth=`echo "$string"
echo $depth
end
the error is the following
testing: line 1: syntax error near unexpected token `('
testing: line 1:... (3 Replies)
Hi All,
Is there any problem with the below 'foreach' loop?
foreach risk_factor ($(cat "$rf_list"))
where "rf_list=$SCRIPT/Utility/rflist.txt "
I'm wondering, it is throwing below error message:
syntax error at line 34: `(' unexpected
Any idea/suggestions ?
Thanks in advance /... (7 Replies)
So I am back again beating my head against the wall with a shell script and getting a headache! I want to change each year in a file (1980, 1981, 1982, 1983, etc.) to the same year followed by a tab.
The input is "blah blah (1980) blah blah".
I want to get "blah blah (1980 ) blah blah".... (2 Replies)
I am trying to make a script for my Counter-Strike: Source servers. What i am wanting it to do is for it to restart each server, the only way i can think of doing this in through for each.
Years what i have at the moment.
server_start() {
START=`ps x | grep SCREEN | grep $SRV | cut -d '?' -f... (5 Replies)
Hi everyone I'm new to unix and encountered a small problem i couldnt find out a reason why it doesn't work..please help..
in my csh script when i tried to use the foreach loop like this:
foreach x ( ls )
echo $x
end
when i tried to run it, it printed out 'ls' to the std out instead of... (3 Replies)
I need to put together a script that will take the contents of two different files (database name and database owner) and put them in two variables within a line:
foreach x (`cat /local/hd3/dba/tools/build_db_scripts/dbs`)
foreach z (`cat /local/hd3/dba/tools/build_db_scripts/dbas`)... (6 Replies)
Discussion started by: deneuve01
6 Replies
LEARN ABOUT SUSE
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[[day] month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week.
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
-V Display version information and exit.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will
be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/.
BSD June 6, 1993 BSD
02-07-2012
)