hello,
I want to replace awk with a perl one liner in unix.
i use in awk REGEX and FS ( field separator) because
awk syntaxes in different unix os versions have not the same behaviour.
i have a file named "file" and want search the exact value (example: search_value) of the first entry (FS="#" ). but there can be some characters at the beginning (REGEXP)
Hi
I am trying to search and replace a multi line pattern in a php file using awk.
The pattern starts with
<div id="navbar">
and ends with
</div>
and spans over an unknown number of lines.
I need the command to be a one liner.
I use the "record separator" like this :
awk -v... (8 Replies)
Thanks for giving your time and effort to answer questions and helping newbies like me understand awk.
I have a huge file, millions of lines, so perl takes quite a bit of time, I'd like to convert these perl one liners to awk.
Basically I'd like all lines with ISA sandwiched between... (9 Replies)
Hi!
I have a difficult problem, to step up a unknown version number in a text file, and save the file. It would be great to run script.sh and the version gets increased.
Example the content of the textfile.txt
hello
version = x
bye
This include three steps
1. First find the char after... (2 Replies)
Hi, I'm writing a ksh script and trying to use an awk / sed / or perl one-liner to remove the last 4 characters of a line in a file if it begins with a period.
Here is the contents of the file... the column in which I want to remove the last 4 characters is the last column. ($6 in awk). I've... (10 Replies)
can someone help me translate the following command, from:
/usr/bin/awk "/^$TOFDAYM $TOFDAYD /,0" $LOGFILE
to something like
perl -e .....
basically, i want to use perl to do awk functions within a shell script. i want to do the above awk, using perl.
any suggestions? (9 Replies)
Hello all
According to the following file (orignal one contains 200x times the same structure...) I was wondering if someone could help me to print <byte>??</byte> values
example, running this script/command like
./script.sh xxapp
I would expect as output: 102 116 112
./script.sh xxapp2... (2 Replies)
Not quite a unix question but problem in a perl command. Taking a chance if someone knows about the error
cat 1
a b c d
perl -p -e 's/a/b/g' 1
b b c d
What is the problem here??
perl -p -i -e 's/a/b/g' 1
Can't remove 1: Text file busy, skipping file. (2 Replies)
Hi,
I am a newbie to awk. Here is my problem. Looking for an awk 1-liner to solve it:
My Computing Environment:
- Solaris10
- I prefer to use csh or sh shells
1. Lets say my input file is File1.dat (delimter = | ) and looks as follows:
(File1.dat)
... (1 Reply)
Trying to find and replace one string with another string in a file
#!/usr/bin/perl
$csd_table_path = "/file.ntab";
$find_str = '--bundle_type=021';
$repl_str = '--bundle_type=021 --target=/dev/disk1s2';
if( system("/usr/bin/perl -p -i -e 's/$find_str/$repl_str/' $csd_table_path")... (2 Replies)
Discussion started by: cillmor
2 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)