Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
dear members,
ls -l
drwxr-xr-x 40 root sys 1024 Jul 11 22:19 usr
drwxr-xr-x 43 root sys 1024 Feb 1 2009 var
i am using solaris 10
is that possibe to do
drwxr-xr-x 40 root sys 1024 25-08-2009 22:19 usr
drwxr-xr-x 43 root sys ... (4 Replies)
Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
I want to change each line so the date format looks like this:
MCOGT23R27815 07/07/27 09/05/27 ... (7 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Discussion started by: prithvirao17
2 Replies
LEARN ABOUT PHP
ssh2_methods_negotiated
SSH2_METHODS_NEGOTIATED(3) 1 SSH2_METHODS_NEGOTIATED(3)ssh2_methods_negotiated - Return list of negotiated methodsSYNOPSIS
array ssh2_methods_negotiated (resource $session)
DESCRIPTION
Returns list of negotiated methods.
PARAMETERS
o $session
- An SSH connection link identifier, obtained from a call to ssh2_connect(3).
RETURN VALUES EXAMPLES
Example #1
Determining what methods were negotiated
<?php
$connection = ssh2_connect('shell.example.com', 22);
$methods = ssh2_methods_negotiated($connection);
echo "Encryption keys were negotiated using: {$methods['kex']}
";
echo "Server identified using an {$methods['hostkey']} with ";
echo "fingerprint: " . ssh2_fingerprint($connection) . "
";
echo "Client to Server packets will use methods:
";
echo " Crypt: {$methods['client_to_server']['crypt']}
";
echo " Comp: {$methods['client_to_server']['comp']}
";
echo " MAC: {$methods['client_to_server']['mac']}
";
echo "Server to Client packets will use methods:
";
echo " Crypt: {$methods['server_to_client']['crypt']}
";
echo " Comp: {$methods['server_to_client']['comp']}
";
echo " MAC: {$methods['server_to_client']['mac']}
";
?>
SEE ALSO ssh2_connect(3).
PHP Documentation Group SSH2_METHODS_NEGOTIATED(3)