Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
dear members,
ls -l
drwxr-xr-x 40 root sys 1024 Jul 11 22:19 usr
drwxr-xr-x 43 root sys 1024 Feb 1 2009 var
i am using solaris 10
is that possibe to do
drwxr-xr-x 40 root sys 1024 25-08-2009 22:19 usr
drwxr-xr-x 43 root sys ... (4 Replies)
Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
I want to change each line so the date format looks like this:
MCOGT23R27815 07/07/27 09/05/27 ... (7 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Discussion started by: prithvirao17
2 Replies
LEARN ABOUT FREEBSD
getopt
GETOPT(1) BSD General Commands Manual GETOPT(1)NAME
getopt -- parse command options
SYNOPSIS
args=`getopt optstring $*` ; errcode=$?; set -- $args
DESCRIPTION
The getopt utility is used to break up options in command lines for easy parsing by shell procedures, and to check for legal options.
Optstring is a string of recognized option letters (see getopt(3)); if a letter is followed by a colon, the option is expected to have an
argument which may or may not be separated from it by white space. The special option '--' is used to delimit the end of the options. The
getopt utility will place '--' in the arguments at the end of the options, or recognize it if used explicitly. The shell arguments ($1 $2
...) are reset so that each option is preceded by a '-' and in its own shell argument; each option argument is also in its own shell argu-
ment.
EXIT STATUS
The getopt utility prints an error message on the standard error output and exits with status > 0 when it encounters an option letter not
included in optstring.
EXAMPLES
The following code fragment shows how one might process the arguments for a command that can take the options -a and -b, and the option -o,
which requires an argument.
args=`getopt abo: $*`
# you should not use `getopt abo: "$@"` since that would parse
# the arguments differently from what the set command below does.
if [ $? -ne 0 ]; then
echo 'Usage: ...'
exit 2
fi
set -- $args
# You cannot use the set command with a backquoted getopt directly,
# since the exit code from getopt would be shadowed by those of set,
# which is zero by definition.
while true; do
case "$1" in
-a|-b)
echo "flag $1 set"; sflags="${1#-}$sflags"
shift
;;
-o)
echo "oarg is '$2'"; oarg="$2"
shift; shift
;;
--)
shift; break
;;
esac
done
echo "single-char flags: '$sflags'"
echo "oarg is '$oarg'"
This code will accept any of the following as equivalent:
cmd -aoarg file file
cmd -a -o arg file file
cmd -oarg -a file file
cmd -a -oarg -- file file
SEE ALSO getopts(1), sh(1), getopt(3)HISTORY
Written by Henry Spencer, working from a Bell Labs manual page. Behavior believed identical to the Bell version. Example changed in FreeBSD
version 3.2 and 4.0.
BUGS
Whatever getopt(3) has.
Arguments containing white space or embedded shell metacharacters generally will not survive intact; this looks easy to fix but is not. Peo-
ple trying to fix getopt or the example in this manpage should check the history of this file in FreeBSD.
The error message for an invalid option is identified as coming from getopt rather than from the shell procedure containing the invocation of
getopt; this again is hard to fix.
The precise best way to use the set command to set the arguments without disrupting the value(s) of shell options varies from one shell ver-
sion to another.
Each shellscript has to carry complex code to parse arguments halfway correctly (like the example presented here). A better getopt-like tool
would move much of the complexity into the tool and keep the client shell scripts simpler.
BSD January 26, 2011 BSD