Hello
I have problem with reg-expr and function gsub();
File that I want to preprocess look like this:
int table ;
printf(" variable : ", variable) ;
Using nawk I try something like this:
for ( .... )
{
line = $0
reg_expr = "\.\=]*" "" variable "" "\.\=]*" ;
gsub( reg_expr... (1 Reply)
Hello,
I have a variable that displays the following results from a JVM....
1602100K->1578435K
I would like to collect the value of 1578435 which is the value after a garbage collection. I've tried the following command but it looks like I can't get the > to work. Any suggestions as... (4 Replies)
Hi all
I want to do a simple substitution in awk but I am getting unexpected output. My function accepts a time and then prints out a validation message if the time is valid. However some times may include a : and i want to strip this out if it exists before i get to the validation. I have shown... (4 Replies)
Being new to awk, I am still running into little stupid things. For this issues I am trying to search for all occurrences of a string in a file and replace all of those occurrences with a replacement string. I tried doing
awk '{gsub("|750101|", "|000000|", $0)}' infile > outfile
Unix... (3 Replies)
Hey,
I would like to replace a string by a new one. Teh problem is that both strings should be variables to be flexible, because I am having a lot of files (with the same structure, but in different folders)
for i in daysim_*
do
cd $i/5/
folder=`pwd |awk '{print $1}'`
awk '{ if... (3 Replies)
Want to extend an array to remove the rest of the field $2. Can anybody suggest the correct code?
This code:
awk 'NR==FNR{x;next}{for(r in x) gsub(r/.*/, "",$2)}1' patternlist infileneither this works:
awk 'NR==FNR{x;next}{for(r in x) r=r+"/.*/" gsub(r/.*/, "",$2)}1' patternlist infile (5 Replies)
I am trying to write my gsub regex to replace a bunch of special characters with spaces, so i can split it to an array and look at each word independently.
However, my regex skills are slightly lacking and I appear to be missing a quote or something here.
I am trying to replace the following... (6 Replies)
Hi, I want to print the first column with original value and without any double quotes
The output should look like
<original column>|<column without quotes>
$ cat a.txt
"20121023","19301229712","100397"
"20121023","19361629712","100778"
"20121030A","19361630412","100838"... (3 Replies)
Hello, I had some difficulty to understand the gsub function and maybe the regex in this script to remove all the punctuations:
awk 'gsub(//, " ", $0)' text.txtFile text.txt:
This is a test for gsub
I typed this random text file
which contains punctuation like ,.;!'"?/\ etc.
The script... (6 Replies)
My file "test.dat" data as below
Requirement is to mask(replace) all english characters with "X" EXCEPT first 7 characters of every line.
my command
awk '{gsub("]","X")}1' test.dat
looks not working properly, Appreciate any suggestion... (6 Replies)
Discussion started by: JSKOBS
6 Replies
LEARN ABOUT CENTOS
xzcmp
XZDIFF(1) XZ Utils XZDIFF(1)NAME
xzcmp, xzdiff, lzcmp, lzdiff - compare compressed files
SYNOPSIS
xzcmp [cmp_options] file1 [file2]
xzdiff [diff_options] file1 [file2]
lzcmp [cmp_options] file1 [file2]
lzdiff [diff_options] file1 [file2]
DESCRIPTION
xzcmp and xzdiff invoke cmp(1) or diff(1) on files compressed with xz(1), lzma(1), gzip(1), bzip2(1), or lzop(1). All options specified
are passed directly to cmp(1) or diff(1). If only one file is specified, then the files compared are file1 (which must have a suffix of a
supported compression format) and file1 from which the compression format suffix has been stripped. If two files are specified, then they
are uncompressed if necessary and fed to cmp(1) or diff(1). The exit status from cmp(1) or diff(1) is preserved.
The names lzcmp and lzdiff are provided for backward compatibility with LZMA Utils.
SEE ALSO cmp(1), diff(1), xz(1), gzip(1), bzip2(1), lzop(1), zdiff(1)BUGS
Messages from the cmp(1) or diff(1) programs refer to temporary filenames instead of those specified.
Tukaani 2011-03-19 XZDIFF(1)