Sponsored Content
Top Forums Shell Programming and Scripting Adding days to system date then compare to a date Post 302593144 by balajesuri on Wednesday 25th of January 2012 08:32:56 PM
Old 01-25-2012
Code:
[ $date -gt `date -d "+6 days" +%Y%m%d` ]

I assume you can "substr" date from each line successfully yourself.
This User Gave Thanks to balajesuri For This Post:
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

adding or subtracting days in the o/p of date

how can we add or subtract days from the output of date command in unix... like if i want to subtract a day from the result of date command like this.. v_date=`date +%Y%m%d` this wud give me 20080519 now i want to subtract one day from this.. so tht it wud give me 20080518.. how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies

2. Shell Programming and Scripting

Compare date from db2 table to yesterday's Unix system date

I am currently running the following Korn shell script which works fine: #!/usr/bin/ksh count=`db2 -x "select count(*) from schema.tablename"` echo "count" I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Discussion started by: sasaliasim
9 Replies

3. Shell Programming and Scripting

Adding days to an input date.

Hello Unix gurus, I need to add days to the input date and further use it in comparision with the existing date. Im having issues sto add days to date,can you guys help me with script or function with which I can add days to the date. Thanks, Sud (10 Replies)
Discussion started by: sud
10 Replies

4. Shell Programming and Scripting

how to get what date was 28 days ago of the current system date IN UNIX

Hi, Anybody knows how to get what date was 28 days ago of the current system date through UNIX script. Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies

5. Windows & DOS: Issues & Discussions

Adding or subtracting days from current date in batch script

Hi, I'm writing an batch file to create report In the batch file iam passing two arguments:startdate and finishdate Ex: startdate=07-sep-2009 finishdate=07-sep-2011 I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Discussion started by: anand1773
2 Replies

6. Shell Programming and Scripting

Adding days to date

Hi, please can somebody let me know the easiest way to add days to a date. I can do this in perl but would like to able to do it in a shell script. Desired output would be: date +'%Y-%m-%d' + 10 = 2016-05-02 Thank you (8 Replies)
Discussion started by: andy391791
8 Replies

7. Shell Programming and Scripting

Compare the system date with date from a text file

I get the date that's inside a text file and assigned it to a variable. When I grep the date from the file, I get this, Not After : Jul 28 14:09:57 2017 GMT So I only crop out the date, with this command echo $dateFile | cut -d ':' -f 2,4The result would be Jul 28 14:57 2017 GMT How do I... (3 Replies)
Discussion started by: Loc
3 Replies

8. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies

9. UNIX for Beginners Questions & Answers

Compare date in .txt with system date and remove if it's lesser than system date

Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt . I don't want to delete... (2 Replies)
Discussion started by: Stuti
2 Replies

10. Answers to Frequently Asked Questions

Compare date in .txt with system date and remove if it's lesser than system date

I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Discussion started by: Stuti
1 Replies
DATETIME.ADD(3) 							 1							   DATETIME.ADD(3)

DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::add (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_add (DateTime $object, DateInterval $interval) Adds the specified DateInterval object to the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.add(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-01'); date_add($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-11 Example #2 Further DateTime.add(3) examples <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-01 10:00:30 2007-06-05 04:03:02 Example #3 Beware when adding months <?php $date = new DateTime('2000-12-31'); $interval = new DateInterval('P1M'); $date->add($interval); echo $date->format('Y-m-d') . " "; $date->add($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.sub(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.ADD(3)
All times are GMT -4. The time now is 06:13 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy