Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
Code:
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if [ date > (date today + 6) ]; then
...proceed commands
fi
done
i need to accurately add 6 days to the current date and compare it to the date i extracted from the file.
Gurus, please help
how can we add or subtract days from the output of date command in unix...
like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me 20080519
now i want to subtract one day from this.. so tht it wud give me 20080518..
how do i do... (1 Reply)
I am currently running the following Korn shell script which works fine:
#!/usr/bin/ksh
count=`db2 -x "select count(*) from schema.tablename"`
echo "count"
I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Hello Unix gurus,
I need to add days to the input date and further use it in comparision with the existing date.
Im having issues sto add days to date,can you guys help me with script or function with which I can add days to the date.
Thanks,
Sud (10 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi,
I'm writing an batch file to create report
In the batch file iam passing two arguments:startdate and finishdate
Ex: startdate=07-sep-2009 finishdate=07-sep-2011
I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Hi, please can somebody let me know the easiest way to add days to a date.
I can do this in perl but would like to able to do it in a shell script.
Desired output would be:
date +'%Y-%m-%d' + 10 = 2016-05-02
Thank you (8 Replies)
I get the date that's inside a text file and assigned it to a variable. When I grep the date from the file, I get this,
Not After : Jul 28 14:09:57 2017 GMT
So I only crop out the date, with this command
echo $dateFile | cut -d ':' -f 2,4The result would be
Jul 28 14:57 2017 GMT
How do I... (3 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Discussion started by: Stuti
1 Replies
LEARN ABOUT MINIX
date
DATE(1) General Commands Manual DATE(1)NAME
date - print or set the date and time
SYNOPSIS
date [-qsu] [[MMDDYY]hhmm[ss]] [+format]
OPTIONS -q Read the date from stdin
-s Set the time (implicit for -q or a date string)
-u Print the date as GMT
-t Use this number of seconds instead of current time
EXAMPLES
date # Print the date and time
date 0221921610 # Set date to Feb 21, 1992 at 4:10 p.m.
DESCRIPTION
With the -q flag or a numeric argument, date sets the GMT time and date. MMDDYY refers to the month, day, and year; hhmmss refers to the
hour, minute and second. Each of the six fields must be exactly two digits, no more and no less. date always display the date and time,
with the default format for the system. The -u flag request GMT time instead of local time. A format may be specified with a + followed
by a printf-like string with the following options:
%% % character
%A Name of the day
%B Name of the month
%D mm/dd/yy
%H Decimal hour on 2 digits
%I Decimal hour modulo 12 on 2 digits
%M Decimal minute on 2 digits
%S Decimal seconds on 2 digits
%T HH:MM:SS
%U Decimal week number, Sunday being first day of week
%W Decimal week number, Monday being first day of week
%X Same as %T
%Y Decimal year on 4 digits
%Z Time Zone (if any)
%a Abbreviated name of the day
%b Abbreviated name of the month
%c Appropriate date & time (default format)
%d Decimal day of the month on 2 digits
%e Same as %d, but a space replaces leading 0
%h Same as %b
%j Decimal dey of the year on 3 digits
%m Decimal month on 2 digits
%n Newline character
%p AM or PM
%r 12-hour clock time with AM/PM
%s Number of seconds since the epoch
%t Tab character
%w Decimal day of the week (0=Sunday)
%x Same as %D
%y Decimal year on 2 digits
SEE ALSO time(2), ctime(3), readclock(8).
DATE(1)
01-25-2012
