Some of the systems (eg Solaris) may not have those features in the 'date' command. If you are looking for portable solution, you may want to use perl. I believe most of the modern system will have perl 4 or above.
Here is my function that you can adopt in your shell script
Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Hi All,
how to get 2 days Old date from current date in shell shell scripting not Perl scripting.
example-toady's date is 01-April-2013
Expected result will be -30-Mar-2013
please consider Leap year and Feb 28 month also.
Thanks,
Krupa (7 Replies)
hi all..
i want 2 know how 2 find 7days past date from current date..
when i used set datetime = `date '+%m%d%y'` i got 060613..
i just want to know hw to get 053013..
i tried using date functions but couldnt get it :( i use c shell and there is no chance that i can change that ..... (3 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
px_date2string
PX_DATE2STRING(3)PX_DATE2STRING(3)px_date2string - Converts a date into a string.SYNOPSIS
string px_date2string (resource $pxdoc, int $value, string $format)
DESCRIPTION
Turns a date as it stored in the paradox file into human readable format. Paradox dates are the number of days since 1.1.0000. This func-
tion is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the example below.
PARAMETERS
o $pxdoc
- Resource identifier of the paradox database as returned by px_new(3).
o $value
- Value as stored in paradox database field of type PX_FIELD_DATE.
o $format
- String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by
date(3) (Y, y, m, n, d, j, L).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Turn a paradox date into a human readable form
<?php
$px = px_new();
/* make up a date as it could be stored in */
/* a date field of a paradox db. */
/* 700000 days since 1.1.0000. */
$days = 700000;
/* Use the calendar functions to print a */
/* human readable format of the date */
echo jdtogregorian($days+1721425)."
";
/* px_date2string() outputs the same */
echo px_date2string($px, $days, "n/d/Y")."
";
px_delete($px);
?>
The above example will output:
7/15/1917
7/15/1917
SEE ALSO px_timestamp2string(3), jdtogregorian(3).
PHP Documentation Group PX_DATE2STRING(3)