Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Hi All,
how to get 2 days Old date from current date in shell shell scripting not Perl scripting.
example-toady's date is 01-April-2013
Expected result will be -30-Mar-2013
please consider Leap year and Feb 28 month also.
Thanks,
Krupa (7 Replies)
hi all..
i want 2 know how 2 find 7days past date from current date..
when i used set datetime = `date '+%m%d%y'` i got 060613..
i just want to know hw to get 053013..
i tried using date functions but couldnt get it :( i use c shell and there is no chance that i can change that ..... (3 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
nwfstime
NWFSTIME(1) nwfstime NWFSTIME(1)NAME
nwfstime - Display / Set a NetWare server's date and time
SYNOPSIS
nwfstime [ -h ] [ -S server ] [ -U user name ] [ -P password | -n ] [ -C ] [ -s ]
DESCRIPTION
nwfstime displays a NetWare server's date and time. You can also set a NetWare server's date and time from the local time.
OPTIONS -h
With -h nwfstime prints a little help text.
-S server
is the name of the server you want to use.
-U user
user is the user name to use for login. To set the server's time, you need supervisor privileges.
-P password
password is the password to use for login. If neither -n nor -P are given, and the user has no open connection to the server, nwfstime
prompts for a password.
-n
-n should be given if no password is required for the login. As you need supervisor privileges for setting the date and time, this
option is probably not used very often.
-C
By default, passwords are converted to uppercase before they are sent to the server, because most servers require this. You can turn off
this conversion by -C.
-s
With -s, nwfstime sets the file server's date and time according to the local date and time.
nwfstime 12/10/1996 NWFSTIME(1)