Hi all,
I'm having problems with the setting a variable in a nested if statement. It doesn't seem to change even if it mets the 'if' condition.
My script essentially looks for a user name from the output from a kerberos command.
When I find the user name, I tried to change a variable and exit... (6 Replies)
Hello I have some nested loop to display files and form menu item.
The part of the code is below.
I found that after runnining the script for a while the display becomes very slow.
Does ksh shell provided any easy way to release variables, reinit, etc.
while ];do
script=0
... (2 Replies)
Hi,
I have the following script which is two while loops, but it is working only for the Inner loop without going back to the outer loop.
the aim of this script is to remove data files from memory after each five times for each setting of the rotate parameter
#!/bin/csh
set hdir =... (1 Reply)
Hi,
How to use values in one for loop to other for loop.
say "$sf_rel" variable has values "2011/W2 2011/G2" I want to use these values in inner for loop to process properly.
$branch variable has G2 and 6
What is happening is outer for loop $i has 2011/W2 it is entering into inner... (3 Replies)
Greetings,
Would anyone be able to tell me why this nested loop doesn't seem to work in any variation?
for i in {1..8}
do
echo "i is "$i
for j in {1..i}
do
echo "j is "$j
done
doneoutput is always along the lines of
i is 1... (7 Replies)
Hi All,
Need help on below script
for g in `cat /home/sid.txt`
do
for h in `cat /home/dev.txt`
do
symmaskdb -sid $g -dev $h list assign |grep FA |head -1|awk '{print $2}' > tt1.txt
done
done
cat /home/sid.txt
**************
123
235
456 (5 Replies)
I have a MPI program like this:
void slave1(int j){
MPI_Status status;
MPI_Recv(&j,1,MPI_INT,0,0,MPI_COMM_WORLD,&status);}
void slave2(int j){
MPI_Status status;
MPI_Recv(&j,1,MPI_INT,0,1,MPI_COMM_WORLD,&status);}
int main(int argc, char *argv){
int numprocs, rank;
... (0 Replies)
I am using the following nested loop
for i in {1..3}
do
for y in {1..3}
do
if ;
then
echo P0${i}R${y}.fas
mv P0${i}R${y}.fas P${i}R${y}.fas
read -t 5
fi
done
done
I was wondering if I can use a character such as * or ? instead of my second variable y. I tried R in... (3 Replies)
Discussion started by: Xterra
3 Replies
LEARN ABOUT DEBIAN
perl6::export
Export(3pm) User Contributed Perl Documentation Export(3pm)NAME
Perl6::Export - Implements the Perl 6 'is export(...)' trait
SYNOPSIS
# Perl 5 code...
package Some::Module;
use Perl6::Export;
# Export &foo by default, when explicitly requested,
# or when the ':ALL' export set is requested...
sub foo is export(:DEFAULT) {
print "phooo!";
}
# Export &var by default, when explicitly requested,
# or when the ':bees', ':pubs', or ':ALL' export set is requested...
# the parens after 'is export' are like the parens of a qw(...)
sub bar is export(:DEFAULT :bees :pubs) {
print "baaa!";
}
# Export &baz when explicitly requested
# or when the ':bees' or ':ALL' export set is requested...
sub baz is export(:bees) {
print "baassss!";
}
# Always export &qux
# (no matter what else is explicitly or implicitly requested)
sub qux is export(:MANDATORY) {
print "quuuuuuuuux!";
}
sub import {
# This subroutine is called when the module is used (as usual),
# but it is called after any export requests have been handled.
# Those requests will have been stripped from its argument list
}
DESCRIPTION
Implements what I hope the Perl 6 symbol export mechanism might look like.
It's very straightforward:
o If you want a subroutine to be capable of being exported (when explicitly requested in the "use" arguments), you mark it with the "is
export" trait.
o If you want a subroutine to be automatically exported when the module is used (without specific overriding arguments), you mark it with
the "is export(:DEFAULT)" trait.
o If you want a subroutine to be automatically exported when the module is used (even if the user specifies overriding arguments), you
mark it with the "is export(:MANDATORY)" trait.
o If the subroutine should also be exported when particular export groups are requested, you add the names of those export groups to the
trait's argument list.
That's it.
WARNING
The syntax and semantics of Perl 6 is still being finalized and consequently is at any time subject to change. That means the same caveat
applies to this module.
DEPENDENCIES
Requires Filter::Simple
AUTHOR
Damian Conway (damian@conway.org)
BUGS AND IRRITATIONS
Does not yet handle the export of variables.
Comments, suggestions, and patches welcome.
COPYRIGHT
Copyright (c) 2003, Damian Conway. All Rights Reserved.
This module is free software. It may be used, redistributed
and/or modified under the same terms as Perl itself.
perl v5.8.8 2008-03-12 Export(3pm)