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Top Forums Shell Programming and Scripting $0 doesn't have full directory path Post 302591462 by gary_w on Thursday 19th of January 2012 02:08:56 PM
Old 01-19-2012
Exactly, that is why you want to strip out the path part of $0 by using basename first.
 

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DIRNAME(3)						     Linux Programmer's Manual							DIRNAME(3)

NAME
dirname, basename - Parse pathname components SYNOPSIS
#include <libgen.h> char *dirname(char *path); char *basename(char *path); DESCRIPTION
The functions dirname and basename break a null-terminated pathname string into directory and filename components. In the usual case, dirname returns the string up to, but not including, the final '/', and basename returns the component following the final '/'. Trailing '/' characters are not counted as part of the pathname. If path does not contain a slash, dirname returns the string "." while basename returns a copy of path. If path is the string "/", then both dirname and basename return the string "/". If path is a NULL pointer or points to an empty string, then both dirname and basename return the string ".". Concatenating the string returned by dirname, a "/", and the string returned by basename yields a complete pathname. Both dirname and basename may modify the contents of path, so if you need to preserve the pathname string, copies should be passed to these functions. Furthermore, dirname and basename may return pointers to statically allocated memory which may be overwritten by subsequent calls. The following list of examples (taken from SUSv2) shows the strings returned by dirname and basename for different paths: path dirname basename "/usr/lib" "/usr" "lib" "/usr/" "/" "usr" "usr" "." "usr" "/" "/" "/" "." "." "." ".." "." ".." EXAMPLE
char *dirc, *basec, *bname, *dname; char *path = "/etc/passwd"; dirc = strdup(path); basec = strdup(path); dname = dirname(dirc); bname = basename(basec); printf("dirname=%s, basename=%s ", dname, bname); free(dirc); free(basec); RETURN VALUE
Both dirname and basename return pointers to null-terminated strings. BUGS
In versions of glibc up to and including 2.2.1, dirname does not correctly handle pathnames with trailing '/' characters, and generates a segmentation violation if given a NULL argument. CONFORMING TO
SUSv2 SEE ALSO
dirname(1), basename(1), GNU
2000-12-14 DIRNAME(3)
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