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Top Forums Shell Programming and Scripting $0 doesn't have full directory path Post 302591462 by gary_w on Thursday 19th of January 2012 02:08:56 PM
Old 01-19-2012
Exactly, that is why you want to strip out the path part of $0 by using basename first.
 

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basename(1)						      General Commands Manual						       basename(1)

Name
       basename - strip directory names from pathname

Syntax
       basename string [ suffix ]

Description
       The  command  deletes from string any prefix up to and including the last slash (/) and the suffix (if specified), and prints the result on
       the standard output.  The command handles limited regular expressions in the same manner as metacharacters must	be  escaped  if  they  are
       intended to be interpreted literally.  For example:
       % basename /vmunix .x
       vmun
       % basename /vmunix '.x'
       vmunix
       In  the	first example, returns because it interprets the as a regular expression consisting of any character followed by the letter In the
       second example, the dot is escaped; there is no match on a dot followed by and returns

       The command is often used inside substitution marks (` `) within shell procedures.

Examples
       The following example shell script compiles the file and moves the output to in the current directory:
       cc /usr/src/bin/cat.c
       mv a.out `basename $1 .c`
       The following example echoes only the base name of the file by removing the prefix and any possible sequence of	characters  following  the
       period in the file's name:
       % basename /etc/syslog.conf '..*'
       syslog

See Also
       dirname(1), ex(1), sh(1)

																       basename(1)
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