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Top Forums UNIX for Dummies Questions & Answers Passing of variable values to remote server Post 302590240 by sree143reddy on Sunday 15th of January 2012 03:18:18 AM
Old 01-15-2012
Passing of variable values to remote server

Hi,
My script will take 3 i/p's from user. Now i need to pass these 3 values to remote server. Please find my code.

Code:
 
while [ 1 ]
do
   echo " To which server you want to connect ? "
   echo " 1. server1 \n"
   echo " 2. server2 \n"
   read opt_server
   if [ $opt_server -eq 1 ]
   then
      echo "enter the file which you want to FTP "
      read $1
      echo " enter into which path you want to FTP the file"
      echo " 1. Path1 \n "
      echo " 2. Path2 \n "
      read $2
      ksh remote_server.ksh $1 $2 
   else
      echo " you din't choose correct option "
      exit
   fi
done

with this code i am not able to pass the values which i am reading from user to the remote_server.ksh, with which i can FTP the required file.

Please help me in this regard.
Thanks in advance.

Thanks,
sreekanth.

Moderator's Comments:
Mod Comment Use code tags please, ty. Indention is also very helpful.

Last edited by zaxxon; 01-15-2012 at 04:49 AM.. Reason: code tags
 

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EVAL(3) 								 1								   EVAL(3)

eval - Evaluate a string as PHP code

SYNOPSIS
mixed eval (string $code) DESCRIPTION
Evaluates the given $code as PHP. Caution The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand. PARAMETERS
o $code - Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g. 'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error, whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe- cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible after it terminates. RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to catch a parse error in eval(3) using set_error_handler(3). EXAMPLES
Example #1 eval(3) example - simple text merge <?php $string = 'cup'; $name = 'coffee'; $str = 'This is a $string with my $name in it.'; echo $str. " "; eval("$str = "$str";"); echo $str. " "; ?> The above example will output: This is a $string with my $name in it. This is a cup with my coffee in it. NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Tip As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of this function, and save it in a string (for example). Note In case of a fatal error in the evaluated code, the whole script exits. SEE ALSO
call_user_func(3). PHP Documentation Group EVAL(3)
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