01-09-2012
For loop to check the files availability
Hi,
I need a help with my script.
Below is my script. What I am doing here is finding the date of the file which I need to process and then finding the list of file names.
Based on the list of file names, check has to be done to see if all the files are there and log the details to a error file.
After finding the SOURCE_FILE_NAME value from the database, I need to check the availability of files, even if one of them is missing, the process has to be failed else it should be success. Check has to be completed for all the files even if one file is missing and then finally log the details and the process should fail.
#!/bin/sh
PHP Code:
date_str=`date "+%Y%m%d%H%M%S"`
errfile=ABC_err_$date_str.log
FileDate=12212011
echo Script $0 started at `date` >${errfile}
###Check for the Trigger_file
if ! [ -f "ABC_Trigger_$FileDate" ]
then
echo "ABC_Trigger_$FileDate doesn't exist" >>${errfile}>&2
Actual_Date=`ls ABC_Trigger_* | sort -t"_" -k3.8 | head -1 | cut -d"_" -f3`
echo $Actual_Date
Date_of_file=$Actual_Date
echo "ABC_Trigger file is ABC_Trigger_$Date_of_file"
else
Date_of_file=$FileDate
fi
####Connect to DB to get the file name###########
SOURCE_FILE_NAME=`sqlplus -s <<sqlEOF
unageq1/pa23403sw@DEVDB
set feedback off
set heading off
set pagesize 0
set echo off
whenever sqlerror exit failure
whenever oserror exit failure
select SOURCE_FILE_NAME||'_$Date_of_file' from source_sys_det WHERE Source_sys_name='ABC' ;
sqlEOF`
echo $SOURCE_FILE_NAME
####transposing the file name and creating a file to check if they are available####
awk '$1=$1' RS= FS="\n" OFS=, $SOURCE_FILE_NAME >>SOURCE_FILE_NAME_LIST
for FILE in $SOURCE_FILE_NAME_LIST
do
if ! [ -f "$FILE" ]
then
echo "$FILE missing" >>${errfile} 2>&1
fi
done
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