I am writing a C program which a part of it needs to padding zero in front of a string. The program will get a sting from an ASCII file which the maxium length of this string is 5 char long. The string can sometimes less the 5 char long. In order to make it with the same length '0's are being... (3 Replies)
Hi
Can anyone tell me how to pad zeroes on the left side to a numeric string in unix shell scripting
Your answer is very much appreciated
Thanks
Vijay (2 Replies)
Is there a function in c that will allow me to pad variables?
I have an int that can't be longer than 10. I need to pad a numeric value with leading zeros
314
0000000314 (1 Reply)
Hi everybody,
I have a question about typesetting. I originally wrote a script for use with ksh and now I am on a system that I cannot modify, and it only has bash.
In the original script I just did typeset -RZ4 variable and it would add the leading zeros. In bash, it doesn't work.
I've... (2 Replies)
Hi Friends,
I would like to left pad with "0's" on first column say (width six)
I have a large file with the format:
FILE:
1: ALFRED 84378 NY
8385: JAMES 88385 FL
323: SMITH 00850 TX
My output needs to be like:
000001: ALFRED 84378 NY
008385: JAMES 88385 FL
000323: SMITH... (10 Replies)
hi All
i am new to linux...
source txt ..
281-BUM-5M BUM-5M 0 0
282-BUM-5M BUM-5M 0 0
83-BUM-5M BUM-5M 0 0
is it possible to use bash script to convert to
(remove the "-" and fill up to 4 digit" ?
0281 BUM-5M BUM-5M 0 0
0282 BUM-5M BUM-5M 0 0
0083 BUM-5M BUM-5M 0 0
thanks a ... (5 Replies)
Hi all
Is there a way to pad the output of a bash script
see that code below
for i in `sed -n '/Start Printer/,/End Printer/p' /u/ab/scripts/hosts.conf | awk '!/^#/ {print $2}' | egrep -v 'broke|primera' `; do
pages=`snmpget -Ov -v1 -c public $i sysLocation.0 | awk '{print $2}'`
... (3 Replies)
Hello people,
I am having problem to sort, sed and zero padding of column in csv file.
7th column only.
Input of csv file:
1,2,3,4,5,6,4/1/2010 12:00 AM,8
1,2,3,4,5,6,3/11/2010 9:39 AM,8
1,2,3,4,5,6,5/12/2011 3:43 PM,8
1,2,3,4,5,6,12/20/2009 7:23 PM,8
Output:... (5 Replies)
I have this csv file that I would like to sort on the 20th and 21st field. They are high lighted below. My challenge is that when I sort on those fields they are not in order as I would have liked. It seems like I have to pad those fields to the longest value in that fields data.
... (6 Replies)
Discussion started by: GroveTuckey
6 Replies
LEARN ABOUT PHP
cubrid_next_result
CUBRID_NEXT_RESULT(3) 1 CUBRID_NEXT_RESULT(3)cubrid_next_result - Get result of next query when executing multiple SQL statementsSYNOPSIS
bool cubrid_next_result (resource $result)
DESCRIPTION
The cubrid_next_result(3) function is used to get results of next query if multiple SQL statements are executed and CUBRID_EXEC_QUERY_ALL
flag is set upon cubrid_execute(3).
PARAMETERS
o $result
-$result comes from a call to cubrid_execute(3)RETURN VALUES
TRUE, when process is successful.
FALSE, when process is unsuccessful.
EXAMPLES
Example #1
cubrid_next_result(3) example
<?php
$conn = cubrid_connect("127.0.0.1", 33000, "demodb", "dba");
$sql_stmt = "SELECT * FROM code; SELECT * FROM history WHERE host_year=2004 AND event_code=20281";
$res = cubrid_execute($conn, $sql_stmt, CUBRID_EXEC_QUERY_ALL);
get_result_info($res);
cubrid_next_result($res);
get_result_info($res);
function get_result_info($req)
{
printf("
------------ get_result_info --------------------
");
$row_num = cubrid_num_rows($req);
$col_num = cubrid_num_cols($req);
$column_name_list = cubrid_column_names($req);
$column_type_list = cubrid_column_types($req);
$column_last_name = cubrid_field_name($req, $col_num - 1);
$column_last_table = cubrid_field_table($req, $col_num - 1);
$column_last_type = cubrid_field_type($req, $col_num - 1);
$column_last_len = cubrid_field_len($req, $col_num - 1);
$column_1_flags = cubrid_field_flags($req, 1);
printf("%-30s %d
", "Row count:", $row_num);
printf("%-30s %d
", "Column count:", $col_num);
printf("
");
printf("%-30s %-30s %-15s
", "Column Names", "Column Types", "Column Len");
printf("------------------------------------------------------------------------------
");
$size = count($column_name_list);
for($i = 0; $i < $size; $i++) {
$column_len = cubrid_field_len($req, $i);
printf("%-30s %-30s %-15s
", $column_name_list[$i], $column_type_list[$i], $column_len);
}
printf("
");
printf("%-30s %s
", "Last Column Name:", $column_last_name);
printf("%-30s %s
", "Last Column Table:", $column_last_table);
printf("%-30s %s
", "Last Column Type:", $column_last_type);
printf("%-30s %d
", "Last Column Len:", $column_last_len);
printf("%-30s %s
", "Second Column Flags:", $column_1_flags);
printf("
");
}
?>
The above example will output:
------------ get_result_info --------------------
Row count: 6
Column count: 2
Column Names Column Types Column Len
------------------------------------------------------------------------------
s_name char 1
f_name varchar 6
Last Column Name: f_name
Last Column Table: code
Last Column Type: varchar
Last Column Len: 6
Second Column Flags:
------------ get_result_info --------------------
Row count: 4
Column count: 5
Column Names Column Types Column Len
------------------------------------------------------------------------------
event_code integer 11
athlete varchar 40
host_year integer 11
score varchar 10
unit varchar 5
Last Column Name: unit
Last Column Table: history
Last Column Type: varchar
Last Column Len: 5
Second Column Flags: not_null primary_key unique_key
SEE ALSO cubrid_execute(3).
PHP Documentation Group CUBRID_NEXT_RESULT(3)