I need to sort a file, the sort is not a alphabetical sort, it's based on a predefined order which is read from a file called fSortOrder.
The format of the fSortOrder file is :
STARTPATH"
....
....
The file that needs to be sorted is called tmpUnsorted and contains data in the format : ... (6 Replies)
Hi there
I need to grep for a detail from a file. The pattern to search for involves escape sequences in it. This causes for the problem.
grep "P\_SOME\_STRING\_SEARCH" filename
Note, I have line like below in the file and expect it to grep.
select *
from my_system_param
... (3 Replies)
I have a file that I am processing with a while loop from, in come cases the grep/sed command (strings record | grep “errorDetail” | sed 's&*errorDetail\(.*)\(/errorDetail\).*&\1&') works and produces the data I am after and in some it does not. I have inspected the data within the failing... (3 Replies)
Hi folks
I am issuing the following command:
grep "" *
Looking for the characters \/:*?"<>|#+%& within all files in a directory, but the command fails being unhappy with pipe:
ksh: 0403-057 Syntax error: `|' is not expected.
How do I force the command to take the pipe | ? I guess... (2 Replies)
Hello,
i have a file called test
hello1
"how" are you4
good"bye"
good7bye
i am trying to print all lines from test that either end with a digit or contain a double quote character anywhere on the line.
i did
grep -n '$' test and was able to print lines ending with digits.
i also did... (2 Replies)
I'm looking for SED equivalent for grep -w -f. All I want is to search a list of patterns from a file. Also If the pattern doesn't match I do not want "null returned", rather I would prefer some text as place holder say "BLANK LINE" as I intend to process the output file based on line number.
... (1 Reply)
Hey guys,
I have a file with an ID which I'm using to grep out the original record from another file. Problem is I have special characters in the original file, and grep is returning only a partial record. How can I get around this?
Appreciate your help!
Pete (3 Replies)
Is there any command or shell script to grep any special character from a file ? I have a huge file containing millions of user names; the requirement is to find names containing special characters.
#!/bin/bash
for i in `cat username.txt`
do
#COMMAND to grep special character
done
... (3 Replies)
Hi,
I have a file which has numerous lines and some of the lines having special characters in it. i want to grep the lines which are having special characters.
say,
one line looks like - %*()$#@"", | acbd
antoher line looks like ***##^%! | efcg
so these kind of lines are present... (5 Replies)
If I have a file like the following
abc.1
abc
abc_1
abc..1
abc*1
abc@1
abc def ghr
def......
ddef 5466 def ed
def** 123445
I`m trying to find exact words from the list
abc
def (4 Replies)
Discussion started by: ritakadm
4 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)