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Full Discussion: SQL Grouping SUM
Top Forums Programming SQL Grouping SUM Post 302587289 by Scott on Wednesday 4th of January 2012 11:52:40 AM
Old 01-04-2012
@Lord Spectre
I had this (in Oracle):
Code:
SQL> select substr(data,0,9), sum(tot) from mytable group by substr(data,0,9);
SUBSTR(DA   SUM(TOT)
--------- ----------
111201/01          5
111201/00         15

(I guess your SQL is MySQL?)
 

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SQL::ReservedWords(3pm) 				User Contributed Perl Documentation				   SQL::ReservedWords(3pm)

NAME
SQL::ReservedWords - Reserved SQL words by ANSI/ISO SYNOPSIS
if ( SQL::ReservedWords->is_reserved( $word ) ) { print "$word is a reserved SQL word!"; } DESCRIPTION
Determine if words are reserved by ANSI/ISO SQL standard. METHODS
is_reserved( $word ) Returns a boolean indicating if $word is reserved by either "SQL:1992", "SQL:1999" or "SQL:2003". is_reserved_by_sql1992( $word ) Returns a boolean indicating if $word is reserved by "SQL:1992". is_reserved_by_sql1999( $word ) Returns a boolean indicating if $word is reserved by "SQL:1999". is_reserved_by_sql2003( $word ) Returns a boolean indicating if $word is reserved by "SQL:2003". reserved_by( $word ) Returns a list with SQL standards that reserves $word. words Returns a list with all reserved words. EXPORTS
Nothing by default. Following subroutines can be exported: is_reserved is_reserved_by_sql1992 is_reserved_by_sql1999 is_reserved_by_sql2003 reserved_by words SEE ALSO
SQL::ReservedWords::DB2 SQL::ReservedWords::MySQL SQL::ReservedWords::ODBC SQL::ReservedWords::Oracle SQL::ReservedWords::PostgreSQL SQL::ReservedWords::SQLite SQL::ReservedWords::SQLServer ISO/IEC 9075:1992 Database languages -- SQL ISO/IEC 9075-2:1999 Database languages -- SQL -- Part 2: Foundation (SQL/Foundation) ISO/IEC 9075-2:2003 Database languages -- SQL -- Part 2: Foundation (SQL/Foundation) AUTHOR
Christian Hansen "chansen@cpan.org" COPYRIGHT
This program is free software, you can redistribute it and/or modify it under the same terms as Perl itself. perl v5.8.8 2008-03-28 SQL::ReservedWords(3pm)
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