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Full Discussion: SQL Grouping SUM
Top Forums Programming SQL Grouping SUM Post 302587282 by Lord Spectre on Wednesday 4th of January 2012 11:48:17 AM
Old 01-04-2012
Nope, I'll elaborate the result after the select. I need directly the SUM for each hour from output SQL select!
Maybe using grouping (and SUM) by partial, but I don't know how to implement yet!

---------- Post updated at 11:48 AM ---------- Previous update was at 11:40 AM ----------

Well, I found myself a solution, it was so simple!!! :-)
Code:
SELECT data, SUM(`tot`) as SUM, COUNT(tot) As HOUR FROM `data` GROUP BY MID(data, 8,2)

Maybe can help some other user! Smilie
 

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SQL::Translator::Parser(3pm)				User Contributed Perl Documentation			      SQL::Translator::Parser(3pm)

NAME
SQL::Translator::Parser - describes how to write a parser DESCRIPTION
Parser modules that get invoked by SQL::Translator need to implement a single function: parse. This function will be called by the SQL::Translator instance as $class::parse($tr, $data_as_string), where $tr is a SQL::Translator instance. Other than that, the classes are free to define any helper functions, or use any design pattern internally that make the most sense. When the parser has determined what exists, it will communicate the structure to the producer through the SQL::Translator::Schema object. This object can be retrieved from the translator (the first argument pass to parse) by calling the schema method: my $schema = $tr->schema; The Schema object has methods for adding tables, fields, indices, etc. For more information, consult the docs for SQL::Translator::Schema and its related modules. For examples of how this works, examine the source code for existing SQL::Translator::Parser::* modules. AUTHORS
Ken Youens-Clark, <kclark@cpan.org<gt>, darren chamberlain <darren@cpan.org>. SEE ALSO
perl(1), SQL::Translator, SQL::Translator::Schema. perl v5.14.2 2012-01-18 SQL::Translator::Parser(3pm)
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