I have a program that will export my data to a single file, but it assigns a file name that is overridden every time I run the program. I need to change the file name to have a sequential number in the filename.
How do I rename a file so that the filename contains the system date and time. I want... (5 Replies)
Hi,
I am new to Unix shell scripting. Can you please help me with this immediate requirement to code.. The requirement is as given below.
In a directory say Y, I have files like this.
PP_100000_28062006_122731_746.dat
PP_100000_28062006_122731_745.dat
PP_100000_28062006_122734_745.dat... (4 Replies)
Hi All,
Sorry to throw this frequent question but I lost my notes on it.
How do you list the files by date? I'm on red hat.
Thanks in advance,
itik (1 Reply)
Hi all,
i'm new here in this forum. I really like the helpful answers in this forum.
Here a short question.
For a script i have to sort files by date and exclude the files of the actual date.
Sorting the files by date and preparing the output for awk is done by this line:
ls -l... (3 Replies)
I know this gets covered quite a bit in the forum and I think there is enough there for me to figure out how to do what I am trying to do, I just don't think I would do it very efficiently so I am going to ask the question...
I have database log files with date and time stamps in the file like
... (7 Replies)
dear all,
i have .dat files named as:
34.dat
2.dat
16.dat
107.dat
i would like to sort them by their filenames as:
2.dat
16.dat
34.dat
107.dat
i have tried numerous combinations of sort and ls command (in vain) to obtain :
107.dat
16.dat
2.dat
34.dat (1 Reply)
Hi all.
I am very new to linux scripting and i have a task i can only solve with a script.
I need to sort files base on the date string in their filenames and create a folder using the same date string then move the files to their respective folders.
Scenario:
Folder Path:... (1 Reply)
Hi all.
I am very new to linux scripting and i have a task i can only solve with a script.
I need to sort files base on the date string in their filenames and create a folder using the same date string then move the files to their respective folders.
Scenario:
Folder Path:... (1 Reply)
I need a unix command which will find all the files greater that a particular date in the file name.
say for example I have files like(filenaming cov : filename.YYDDMMSSSS.txt)
abc.201206015423.txt
abc.201207013456.txt
abc.201202011234.txt
abc.201201024321.txt
efg.201202011234.txt... (11 Replies)
Hi,
I have a list of log files as follows:
name_date_0001_ID0.log
name_date_0001_ID2.log
name_date_0001_ID1.log
name_date_0002_ID2.log
name_date_0004_ID0.log
name_date_0005_ID0.log
name_date_0021_ID0.log
name_date_0025_ID0.log
.......................................... (4 Replies)
Discussion started by: alex2005
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)