Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Shared memory between two c program
Top Forums Programming Shared memory between two c program Post 302584300 by tafazzi87 on Thursday 22nd of December 2011 05:49:29 PM
Old 12-22-2011
i've another problem, now i want to add two numbers and print result, two number are written in the first and second elements of buffer of shared memory and after call an adder program and he make sum and put it into third element of buffer so the main program prints result.
well if i have 3+5 program give 114678723
why?
this is the code for main:
Code:
#include <sys/types.h>
#include <sys/sem.h>
#include <errno.h>
#include <unistd.h>
#include <stdio.h>
#include <sys/shm.h>
#include <sys/ipc.h>
#include <stdlib.h>
#define SEMPERM 0600

typedef union _semun {
    int val;
    struct semid_ds *buf;
    unsigned short *array;
}semun;
int initsem (key_t semkey){
    int status=0, semid;
    semid=semget(semkey, 1 , SEMPERM | IPC_CREAT | IPC_EXCL);
    if (semid==-1){
        if (errno==EEXIST){semid=semget(semkey,1,0);}
    } else {
        semun arg;
        arg.val=0;
        status=semctl(semid,0,SETVAL,arg);
    }
    if ((semid==-1) || (status==-1)){
        perror("initsem fallita");
        return (-1);
    }
    return (semid);
}
int waitSem(int semid){
    struct sembuf wait_buf;
    wait_buf.sem_num=0;
    wait_buf.sem_op=1;
    wait_buf.sem_flg=SEM_UNDO;
    if (semop(semid,&wait_buf, 1)==-1){
        perror("waitSem Fallita");
        exit(-1);
    }
    return 0;
}

int signalSem (int semid){
    struct sembuf signal_buf;
    signal_buf.sem_num=0;
    signal_buf.sem_op=1;
    signal_buf.sem_flg=SEM_UNDO;
    if (semop(semid,&signal_buf,1)==-1){
        perror("signalSem fallita");
        exit(1);
    }
    return 0;
}
int main (){
    key_t chiavemem=0x100,keysem=0x050;
    int sem,a,id,*point;
    pid_t figlio;
    int buffer[2];
    sem=initsem(keysem);
    if(sem<0){
        perror ("creazione semaforo fallita");
        exit (-1);
    }
    id=shmget(chiavemem,sizeof(buffer[2]),0777 |IPC_CREAT);
    if (id<0){
        perror("id main errato");
        exit(-1);
    }
    point=(int *)shmat(id,NULL,0);
    if (point<0){
        perror ("Errato attacco main");
        exit (-1);
    }
    waitSem(sem);
    point[0]=3;
    point[1]=5;
    signalSem(sem);
    figlio=fork();
    if (figlio<0){
        perror("fork fallita");
        exit (-1);
    }
    if (figlio==0){
        execvp("/home/francesco/NetBeansProjects/Esercizio1/addizione",NULL);
        a=point[2];
        fflush(stdout);
        exit(0);
    }
    printf("il risultato è %d",a);
    shmdt(point);
    shmctl(id,IPC_RMID,0);
    exit(0);
}

instead adder is:
Code:
#include <sys/types.h>
#include <sys/sem.h>
#include <errno.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
#include <sys/shm.h>
#include <sys/ipc.h>
#define SEMPERM 0600

typedef union _semun {
    int val;
    struct semid_ds *buf;
    unsigned short *array;
}semun;
int initsem (key_t semkey){
    int status=0, semid;
    semid=semget(semkey, 1 , SEMPERM | IPC_CREAT | IPC_EXCL);
    if (semid==-1){
        if (errno==EEXIST){semid=semget(semkey,1,0);}
    } else {
        semun arg;
        arg.val=0;
        status=semctl(semid,0,SETVAL,arg);
    }
    if ((semid==-1) || (status==-1)){
        perror("initsem fallita");
        return (-1);
    }
    return (semid);
}
int waitSem(int semid){
    struct sembuf wait_buf;
    wait_buf.sem_num=0;
    wait_buf.sem_op=1;
    wait_buf.sem_flg=SEM_UNDO;
    if (semop(semid,&wait_buf, 1)==-1){
        perror("waitSem Fallita");
        exit(-1);
    }
    return 0;
}

int signalSem (int semid){
    struct sembuf signal_buf;
    signal_buf.sem_num=0;
    signal_buf.sem_op=1;
    signal_buf.sem_flg=SEM_UNDO;
    if (semop(semid,&signal_buf,1)==-1){
        perror("signalSem fallita");
        exit(1);
    }
    return 0;
}
int main(){
    int id,*point,a,b,c;
    key_t keysem=0x050,chiavemem=0x100;
    int sem,buffer[2];
    sem=initsem(keysem);
    if (sem<0){
        perror("errore creazione semaforo");
        exit(-1);
    }
    id=shmget(chiavemem,sizeof(buffer[2]),0777|IPC_CREAT|IPC_EXCL);
    if(id<0){
        perror("errore creazione memoria condivisa");
        exit(-1);
    }
    point=(int *)shmat(id,NULL,0); 
    if (point<0){
        perror("Attacco additore errato");
        exit(-1);
    }
    waitSem(sem);
    point[0]=a;
    point[1]=b;
    c=a+b;
    point[2]=c;
    signalSem(sem);
    shmdt(point);
    exit(0);
}

P.S. Merry Christmas
 

10 More Discussions You Might Find Interesting

1. Programming

Shared memory

Dear Reader, Is is necessary to attach / dettach the shared memory segments for write operations , if more than one program is accessing same shared memory segments.. I have used semaphore mutex and still I'm getting segmentation fault when I write to the segment when other program is already... (1 Reply)
Discussion started by: joseph_shibu
1 Replies

2. UNIX for Advanced & Expert Users

Shared memory shortage but lots of unused memory

I am running HP-UX B.11.11. I'm increasing a parameter for a database engine so that it uses more memory to buffer the disk drive (to speed up performance). I have over 5GB of memory not being used. But when I try to start the DB with the increased buffer parameter I get told. "Not... (1 Reply)
Discussion started by: cjcamaro
1 Replies

3. Linux

all about shared memory

Hi all :confused: , I am new to unix.I have been asked to implement shared memory in user's mode.What does this mean?What is the difference it makes in kernel mode and in users mode?What are the advantages of this impemenation(user's mode)? And also i would like to know why exactly shared... (0 Replies)
Discussion started by: vijaya2006
0 Replies

4. Programming

help with shared memory

what i want to do is have an int that can been written into by 2 processes but my code doesn't seem to work. #include <sys/types.h> #include <sys/ipc.h> #include <sys/sem.h> #include <sys/shm.h> #include<stdio.h> #define KEY1 (1492) int main() { int shmid; volatile int * addr;... (6 Replies)
Discussion started by: ddx08
6 Replies

5. Programming

memory sharing - not shared memory -

hi, this is the problem: i want to swap a linked list between 4 processes (unrelated), is there any way i can do that just by sending a pointer to a structure? //example typedef struct node { int x; char c; struct node *next; } node; or i should send the items ( x,c ) by... (9 Replies)
Discussion started by: elzalem
9 Replies

6. Programming

Shared memory in shared library

I need to create a shared library to access an in memory DB. The DB is not huge, but big enough to make it cumbersome to carry around in every single process using the shared library. Luckily, it is pretty static information, so I don't need to worry much about synchronizing the data between... (12 Replies)
Discussion started by: DreamWarrior
12 Replies

7. Programming

Shared memory for shared library

I am writing a shared library in Linux (but compatible with other UNIXes) and I want to allow multiple instances to share a piece of memory -- 1 byte is enough. What's the "best" way to do this? I want to optimize for speed and portability. Obviously, I'll have to worry about mutual exclusion. (0 Replies)
Discussion started by: otheus
0 Replies

8. UNIX for Advanced & Expert Users

Shared Memory

Hi, Using ipcs we can see shared memory, etc.. details. How can I add/remove shared memory(command name)? Thanks, Naga:cool: (2 Replies)
Discussion started by: Nagapandi
2 Replies

9. AIX

shared memory

1.How to know wich process is using the shared memory? 2.How to flush (release) the process from the shared memory? (1 Reply)
Discussion started by: pchangba
1 Replies

10. Programming

Shared library with acces to shared memory.

Hello. I am new to this forum and I would like to ask for advice about low level POSIX programming. I have to implement a POSIX compliant C shared library. A file will have some variables and the shared library will have some functions which need those variables. There is one special... (5 Replies)
Discussion started by: iamjag
5 Replies
All times are GMT -4. The time now is 06:04 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy