Hi,
My input file is
$cat samp
1 siva
1 raja
2 siva
1 siva
2 raja
4 venkat
i want sort this name wise...alos need to remove duplicate lines.
i am using
cat samp|awk '{print $2,$1}'|sort -u
it showing
raja 1 (3 Replies)
I now have a 230,000+ lines long text file formatted in segments like this:
Is there a way to sort this file to have everything in chronological order, based on the date and time in the text? In this example, I would like the result to be: (19 Replies)
Right now there is no unix direct commad that can sort the files base on its name having numbers:
We can use the following:
In case your file name are like:
abc-UP018.zip
xyz-UP019.zip
ls *|sort -t'-' -k2 (2 Replies)
Experts
I have a list of files in the directory
mysample1
mysample2
mysample3
mysample4
mysample5
mysample6
mysample7
mysample8
mysample9
mysample10
mysample11
mysample12
mysample13
mysample14
mysample15 (4 Replies)
I have a file (input) I want to sort the file based on the number of times a pattern in the first column occurs for example grapes occurs 4 times in combination with other patterns so i want it to be first like shown in the output file. then apple ocuurs thrice so it occupies second position and so... (7 Replies)
Hello,
For example:
12........6789101112..............20212223242526..................50 ( Positions)
LName FName DOB (Lastname starts from 1 to 6 , FName from 8 to 15 and date of birth from 21 to29)
CURTIS KENNETH ... (5 Replies)
Hi,
Need to sort file based on the number of delimeters in the lines.
cat testfile
/home/oracle/testdb
/home
/home/oracle/testdb/newdb
/home/oracle
Here delimeter is "/"
expected Output:
/home/oracle/testdb/newdb
/home/oracle/testdb
/home/oracle
/home (3 Replies)
I have a csv file as shown below,
xop_thy 80 avr_njk 50 str_nyu 60
avr_irt 70 str_nhj 60 avr_ngt 50
str_tgt 80 xop_nmg 50 xop_nth 40
cyv_gty 40 cop_thl 40 vir_tyk 80
vir_plo 20 vir_thk 40 ijk_yuc 70
cop_thy 70 ijk_yuc 80 irt_hgt 80
I need to align/sort the csv file based... (7 Replies)
Discussion started by: dineshkumarsrk
7 Replies
LEARN ABOUT CENTOS
wrap-and-sort
WRAP-AND-SORT(1) General Commands Manual WRAP-AND-SORT(1)NAME
wrap-and-sort - wrap long lines and sort items in Debian packaging files
SYNOPSIS
wrap-and-sort [options]
DESCRIPTION
wrap-and-sort wraps the package lists in Debian control files. By default the lists will only split into multiple lines if the entries are
longer than 80 characters. wrap-and-sort sorts the package lists in Debian control files and all .install files. Beside that wrap-and-sort
removes trailing spaces in these files.
This script should be run in the root of a Debian package tree. It searches for control, control.in, copyright, copyright.in, install, and
*.install in the debian directory.
OPTIONS -h, --help
Show this help message and exit.
-a, --wrap-always
Wrap all package lists in the Debian control file even if the entries are shorter than 80 characters and could fit in one line line.
-s, --short-indent
Only indent wrapped lines by one space (default is in-line with the field name).
-b, --sort-binary-packages
Sort binary package paragraphs by name.
-k, --keep-first
When sorting binary package paragraphs, leave the first one at the top. Unqualified debhelper(7) configuration files are applied to
the first package.
-n, --no-cleanup
Do not remove trailing whitespaces.
-d path, --debian-directory=path
Location of the debian directory (default: ./debian).
-f file, --file=file
Wrap and sort only the specified file. You can specify this parameter multiple times. All supported files will be processed if no
files are specified.
-v, --verbose
Print all files that are touched.
AUTHORS
wrap-and-sort and this manpage have been written by Benjamin Drung <bdrung@debian.org>.
Both are released under the ISC license.
DEBIAN Debian Utilities WRAP-AND-SORT(1)