I want to output screen messages to a logfile when executing an automated script. I have tried the script and command to do this but with no luck.
Thanks,
Nicole (5 Replies)
I need to extract the date part from the file name (20080221 in this ex) and compare it with the current date and delete it, if it is a past date.
$file = exp_ABCD4_T-2584780_upto_20080221.dmp.Z
really appreciate any help.
thanks
mkneni (4 Replies)
Hi,
I need to write a script, that will take the current date, time, and the output from # ps -eo pid,tid,class,rtprio,ni,pri,psr,pcpu,stat,wchan:14,comm
and spit it to a file, so it'll look like this...
PID TID CLS RTPRIO NI PRI PSR %CPU STAT WCHAN COMMAND
1 1 TS... (2 Replies)
do you have any simple script on how to change the color and font of a string in a script example
echo "===================================="
echo " sample color script"
echo "===================================="
echo " hello "
echo " bye"
on hello,... (3 Replies)
Hello gurus,
I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4:
NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~... (4 Replies)
Hi Guys,
Anyone who knows how to compare the current date with the a file containing a date, say for example I have a file that looks like this:
Command was launched from partition 0.
------------------------------------------------
Executing command in server server6
Fri Dec 16... (7 Replies)
Hi guys,
brand new to this thread and very very new to UNIX...so go easy please!
Anyway I have a file that looks like this:
>>--------------------------------------------------------------------------
Date/Time/Eng. : 2012-06-22 / 00:26 / DS
Reported problem : (SD) ... (5 Replies)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
We want to call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below:
abc.txt
------------------
Code:
line1
line2
line3
$$EDWS_DATE_INSERT=08-27-2019
line4
$$EDWS_PREV_DATE_INSERT=08-26-2019
I am trying to write a... (3 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT LINUX
rearj
REARJ(1) Arj Software REARJ(1)NAME
rearj - Converts other archive formats to .arj files
SYNOPSIS
rearj [options] <!listfile(s)|filespec(s)|wildname(s)>
DESCRIPTION
The rearj command can repackage other archive formats to arj.
OPTIONS
-+ Ignore REARJ_SW variable.
-a[suffix]
Convert archives within archives ("*" for all formats).
-bcommand
Execute command before extracting files.
-ccommand
Execute command on extracted files before counting them.
-d Delete original archives.
-e No error switch.
-f Convert diskette archives.
-g Skip creation of output archive.
-i[name]
Check integrity of rearj program.
-j Skip if output archive size is larger than the original.
-k Skip archive timestamping.
-l[name]
Write append log file (default name is rearj.log).
-m[date]
Select archives before date in YYMMDDHHMMSS format.
-n[date]
Select archives on or after date in YYMMDDHHMMSS format.
-o Allow overwrite of existing target archive.
-p Ignore long filenames under Windows 95.
-q Query for each archive to convert.
-r Recurse through subdirectories.
-s Skip verify of file count and total size.
-tsuffix
Create suffix type archives.
-u[bak]
Allow update of archive with backup (default is BAK).
-v Execute configured command on extracted files.
-wdir Assign work directory.
-x[!]file
Exclude by filename, wildname, or listfile.
-y[text]
Delete output archive and write text to log (testing mode).
-z Simulate operation.
ENVIRONMENT
REARJ_SW If set, its value will be used as command line options.
EXIT STATUS
0 Success.
1 File not found.
2 File is not a configured archive type.
3 Target archive already exists.
4 Not enough disk space.
5 User skipped or user did not select update option.
6 UNPACK command error.
7 PACK command error.
8 Target cannot support directories.
9 Wrong file count.
10 Wrong total size.
11 Internal archive REARJ error.
12 Rename archive error.
13 Invoked -v command error (found a virus?).
14 Output archive is larger.
EXAMPLE
rearj * -r -d
Convert all archives to ARJ format, searching all subdirectories, deleting original archives.
SEE ALSO arj(1).
AUTHOR
This manual page was written by Ola Lundqvist <opal@debian.org> in pod format, then converted by Guillem Jover <guillem@debian.org> to
nroff format.
3.10 2003-03-10 REARJ(1)
12-22-2011
