The easiest way is inserting space after 3rd column character in all lines. It assumes fixed width fields:
Wouldn't that cause the lines without the issue to be double spaced?
Could I use something like this:
---------- Post updated at 01:53 PM ---------- Previous update was at 01:51 PM ----------
Quote:
Originally Posted by ctsgnb
Maybe you should contact your vendor : adding a space will not tell you wether the field has been truncated or not.
I think this is up to your vendor to ensure that the generated report that is sent to you does not contain truncated values.
Of course, if you are sure that those fields never contain truncated values, then, indeed, you can separate them as per Bartus suggestion.
I'd agree with you normally, but they are a real pain, and turn around time would be lengthy. The actual end purpose would still work out, (dose not need to be exact) the first few place values would suffice.
Let's say I write a simple script that contains the following:
date | awk '{print $1}'
date | awk '{print $2}'
Of course, when I run the script the output will look similar to:
Tue
Mar
What if I want my ouput to be on one line as follows:
Tue Mar
What changes would I need to... (2 Replies)
I have 2 files with sample data enclosed.
1. GL (already sorted in ascending order by Gl number)
Gl number*glname*Year*opening balance
1000*Interest Income*2006*100.00
1005*Rental Income*2006*0.00
...
2. Transactions (file is not sorted on GL number or any other field)
Branch*Year*Gl... (12 Replies)
Hi
I am fetcthing the data from the oracle database using SQLPLUS. Here is my script
#!/bin/ksh
echo `sqlplus -s <<EOF
set feedback off
set linesize 5000
set pages 0
set space 0
set echo off
set trimspool on
set colsep '|'
SELECT col1 , col2... (4 Replies)
Dear all
I require help with AWK regarding this situation
Input is :
fn1 12345
fn1 23456
fn3 231513
fn1 22325
fn3 123125
Desired output is
fn1 12345 23456 22325
fn3 231513 123125 (5 Replies)
when i try this awk its giving out put as below.
awk '!(/^$/||/--/||/selected/||/^ *$/){print $1}' tmp.txt
output
=====
1
2010-08-03-12.31.26.126000
how excluede the 1st line ? i mean i want output only 2nd line i.e 2010-08-03-12.31.26.126000; (5 Replies)
Hi;
i m running an command like;
getfacl $(find /home/fstl/testShell/ -type f -ls | awk '{print $11}')
and i m getting outpiut for all files in "testShell" folder as;
# file: home/fstl/testShell/.script1.sh.swp
# owner: root
# group: root
user:fstl:rw-
user:ajay:rw-
group:root:r--... (1 Reply)
Hi all,
I'm writing a simple awk code:
awk 'BEGIN {FS="|"};{print "Type\tNumber\ttypes\tTotal";};{print $1, "\t", $2, "\t", $3, "\t", $4, "\t";}' db_query.txt
it gives me the result:
Type Number types Total
XXX 498.0 5100.0 5274.661
Type Number types Total... (7 Replies)
Data
I was trying to write shell script which will be return the output in the below format
First i was trying to do these using sed.
sed -n '/.ksh/p' mainksh.ksh
sed -e 's/*\(.*\)/\1/g' mainksh.ksh
$RUN_DIR, $SUB_DIR and the variables which will be defined in the profile file.
when i am... (0 Replies)
Hi ,
I was trying to find files of a particular date and did that but then I also wanted to format a field based on some condition so had put another if else in awk.
Now it is getting the files of particular date or also the files which are matching that if else condition.
find . -name "*"... (1 Reply)
i would like to format the 9 character with suffix as "0".
i tried below it doesn't work.
>a=12345
> echo $a | awk '{printf "%-09s\n",$1}'
>12345
required output is 123450000
can you guys help me out ? (7 Replies)