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Full Discussion: script for get lines with specific date
Top Forums Shell Programming and Scripting script for get lines with specific date Post 302583588 by michlix on Tuesday 20th of December 2011 09:23:54 PM
Old 12-20-2011
Quote:
Originally Posted by Chubler_XL
For anything from 1900-1999 try:

Code:
grep "WITA 19[0-9][0-9]$" logfile

I write the code
Code:
file=/print/printqeueu
file1=/print/printqeueu1
awk '$6 < 20 {print}' $file > $file1

but i must manual edit on script every change of date, for example 20.
how to get the date 3 days before today ?
 

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LEARN ABOUT DEBIAN

ubuntu-distro-info

UBUNTU-DISTRO-INFO(1)					      General Commands Manual					     UBUNTU-DISTRO-INFO(1)

NAME

       ubuntu-distro-info - provides information about Ubuntu's distributions

SYNOPSIS

       ubuntu-distro-info [OPTIONS]

OPTIONS

       --date=DATE
	      date for calculating the version (default: today)

       -h, --help
	      display help message and exit

       -a, --all
	      list all known versions

       -d, --devel
	      latest development version

       --lts  latest long term support (LTS) version

       -s, --stable
	      latest stable version

       --supported
	      list of all supported stable versions

       --unsupported
	      list of all unsupported stable versions

       -c, --codename
	      print the codename (default)

       -r, --release
	      print the release version

       -f, --fullname
	      print the full name

SEE ALSO

       debian-distro-info(1), distro-info(1)

AUTHOR

       The script and this manual page was written by Benjamin Drung <bdrung@debian.org>.

distro-info							   January 2011 					     UBUNTU-DISTRO-INFO(1)
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