You asked the script to print out the file handle every time it encountered a valid record, so it did
Try this code, it takes a list of input file names as arguments on the command line.
Code:
#!/usr/bin/perl
use strict;
use warnings;
my $out_file = 'output.txt';
open (my $out_fh,'>',$out_file)||die "Couldn't open file $out_file:\n\t$!";
for my $in_file (@ARGV){
open(my $in_fh, '<', $in_file or die "Couldn't open file $in_file:\n\t $!";
while (<$in_fh>){
chomp;
if ($_ =~ /^Customer ID: Yes/){
my $line = readline($in_fh);
print $out_fh $line;
}
}
close $in_fh or die "Could not close file $in_file: $!";
}
close $out_fh or die "Could not close file $out_file: $!";
How exactly do you wish to present the data as a spreadsheet?
Last edited by Skrynesaver; 12-20-2011 at 10:16 AM..
I know this must be really easy, but i can't get it to work
I've got a perl script, with a file.
I want to print an empty line, and the following doesn't seem to work:
print nameoffile "\n"
thanks for your help!! (3 Replies)
Hi
I have a log file (say log.txt). I have to search for a line which has the string ( say ERROR) in the log file and copy 15 lines after this into another file (say error.txt). Can someone give me the code and this has to be in PERL
Thanks in advance
Ammu (3 Replies)
Hello,
I'm trying to create a program in perl called myfind.pl;
To use the program:
(at the command line)$ program.pl keyword filename
note: the keyword is any word or regular expression
and it should display the result just like when you 'cat' the file name but with the keyword in... (2 Replies)
I am trying to find a way to utilise the full potential of my cpu cores and memory on my windows machine.
Now, I am quite familiar with grep, however, running a Unix based OS is not an option right now.
Unfortunately, the 32 bit grep for windows that I am running, I cannot run multiple... (1 Reply)
so in unix this command works works and shows me a list of directories
find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt
but when i try running a perl script to run this command
my $query = 'find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt';... (2 Replies)
Hi,
I would like to know how do I print the line # in a script. My requirement is, I have a script which is about ~5000 lines long. If there are any errors happen I just exit. And I would like to add the line # of the script where the error happened.
Thanks, (6 Replies)
I'm having a script which outputs four different attributes A, B, C, D for a list of users.
I want to insert expression such that once the output is generated for first user, output for next user should be printed in new line.
Please help. (4 Replies)
Florida State University, Tallahassee, FL, USA, Dr. Whalley, COP4342 Unix Tools.
This program takes much of my previous assignment but adds the functionality of printing the concatenated line numbers found within the input.
Sample input from <> operator:
Hello World
This is hello
a sample... (2 Replies)
hi All ,
I am having a large file with lots of modules as shown below
###############################################
module KKK
kksd
kskks
jsn;lsm
jsnlsn;
Ring
jjsjsj
kskmsm
jjs
endmodule
module llll
1kksd11
k232skks
j33sn;l55sm (6 Replies)
Need assistance in getting a shell program .
I have csv file and each line has comma separated number. I wanted to take of the comas and print each number in each line . below example. Appreicate your help
Row with number
... (14 Replies)
Discussion started by: ajayram_arya
14 Replies
LEARN ABOUT DEBIAN
h5jam
h5jam(1) General Commands Manual h5jam(1)NAME
h5jam - Add a user block to a HDF5 file
SYNOPSIS
h5jam -u user_block -i in_file.h5 [-o out_file.h5] [--clobber]
DESCRIPTION
h5jam concatenates a user_block file and an HDF5 file to create an HDF5 file with a user block. The user block can be either binary or
text. The output file is padded so that the HDF5 header begins on byte 512, 1024, etc.. (See the HDF5 File Format.)
If out_file.h5 is given, a new file is created with the user_block followed by the contents of in_file.h5. In this case, infile.h5 is
unchanged.
If out_file.h5 is not specified, the user_block is added to in_file.h5.
If in_file.h5 already has a user block, the contents of user_block will be added to the end of the existing user block, and the file
shifted to the next boundary. If --clobber is set, any existing user block will be overwritten.
EXAMPLE USAGE
Create new file, newfile.h5, with the text in file mytext.txt as the user block for the HDF5 file file.h5.
h5jam -u mytext.txt -i file.h5 -o newfile.h5
Add text in file mytext.txt to front of HDF5 dataset, file.h5.
h5jam -u mytext.txt -i file.h5
Overwrite the user block (if any) in file.h5 with the contents of mytext.txt.
h5jam -u mytext.txt -i file.h5 --clobber
RETURN VALUE
h5jam returns the size of the output file, or -1 if an error occurs.
CAVEATS
This tool copies all the data (sequentially) in the file(s) to new offsets. For a large file, this copy will take a long time.
The most efficient way to create a user block is to create the file with a user block (see H5Pset_user_block), and write the user block
data into that space from a program.
The user block is completely opaque to the HDF5 library and to the h5jam and h5unjam tools. The user block is simply read or written as a
string of bytes, which could be text or any kind of binary data. It is up to the user to know what the contents of the user block means
and how to process it.
When the user block is extracted, all the data is written to the output, including any padding or unwritten data.
This tool moves the HDF5 file through byte copies, i.e., it does not read or interpret the HDF5 objects.
SEE ALSO h5dump(1), h5ls(1), h5diff(1), h5import(1), gif2h5(1), h52gif(1), h5perf(1), h5unjam(1).
h5jam(1)
12-20-2011
