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Full Discussion: passing float parameter
Top Forums Programming passing float parameter Post 302583168 by migurus on Monday 19th of December 2011 07:38:52 PM
Old 12-19-2011
passing float parameter
I am surprised by GCC (this is ver. 4.2.4, Ubuntu 32 bit Intel) when a function declares a float parameter and it's prototype is missing, the parameters are messed up.

Please see my code below:
Code:
~/test$ cat x1.c
#include <stdio.h>
#include <stdlib.h>
set_p(int p1, float p2, int p3, int p4)
{
        printf("p1=%i\n", p1);
        printf("p2=%.4f\n", p2);
        printf("p3=%i\n", p3);
        printf("p4=%i\n", p4);
        return(0);
}
main(int argc, char *argv[])
{
  float x1 = (argc == 2) ? atof(argv[1]) : 1.2345;
        set_p(1, x1, 2, 3);
        set_P(1, x1, 2, 3);
        return(0);
}
~/test$ cat x2.c
#include <stdio.h>
set_P(int p1, float p2, int p3, int p4)
{
        printf("p1=%i\n", p1);
        printf("p2=%.4f\n", p2);
        printf("p3=%i\n", p3);
        printf("p4=%i\n", p4);
        return(0);
}
 
I make it like this:
cc -c x1.c
cc -c x2.c
cc x1.o x2.o

The output:
Code:
~/test$ ./a.out
p1=1
p2=1.2345
p3=2
p4=3
p1=1
p2=0.0000
p3=1072939139
p4=2

As you see, the set_P function somehow messed up parameters.

***Note: the code does work on SCO with stock compiler on similar h/w.

If I add the function prototype to x1.c

Code:
int set_P(int , float , int , int );

then everything works correctly, no surprises.


My understanding is that compiler allocates longs for longs/integers/shorts and doubles for float/double when passing parametrs by value. Then if receiver function expects a float, it will get first 32 bit, which is OK on Intel. Apparently my understanding is not correct.

The code in many places lacks function prototypes, I wander if I can somehow influence compiler to pass float/double parameters and not mess up. Any ideas?
 

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GMAGICKDRAW(3)								 1							    GMAGICKDRAW(3)

The GmagickDraw class

INTRODUCTION

CLASS SYNOPSIS

       GmagickDraw

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