12-12-2011
regex date format help
I need to write a regular expression for todays date in format 12/11/11? any help will be greatful thanks.
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hi there
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xpnl_hypo_reu_miplvdone_11-17-2011.csv
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$ awk '{print $1," ",$4}' access.log | sort | uniq -c| sort -nr | head -n20
62 192.168.10.6
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62, 192.168.10.6, 14:40
62, 192.168.10.32, 47:57
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LEARN ABOUT ULTRIX
re_exec
regex(3) Library Functions Manual regex(3)
Name
re_comp, re_exec - regular expression handler
Syntax
char *re_comp(s)
char *s;
re_exec(s)
char *s;
Description
The subroutine compiles a string into an internal form suitable for pattern matching. The subroutine checks the argument string against
the last string passed to
The subroutine returns 0 if the string s was compiled successfully; otherwise a string containing an error message is returned. If is
passed 0 or a null string, it returns without changing the currently compiled regular expression.
The subroutine returns 1 if the string s matches the last compiled regular expression, 0 if the string s failed to match the last compiled
regular expression, and -1 if the compiled regular expression was invalid (indicating an internal error).
The strings passed to both and may have trailing or embedded newline characters; they are terminated by nulls. The regular expressions
recognized are described in the manual entry for given the above difference.
Diagnostics
The subroutine returns -1 for an internal error.
The subroutine returns one of the following strings if an error occurs:
No previous regular expression
Regular expression too long
unmatched (
missing ]
too many () pairs
unmatched )
See Also
ed(1), ex(1), egrep(1), fgrep(1), grep(1)
regex(3)