Hi,
I have a situation where I have to specify a different value to an awk command, I beleive i have the gist of this done, however I am not able to get this correct. Here is what I have so far
echo $id
065859555
This value occurs in a "pipe" delimited file in postition 8. Hence I would... (1 Reply)
Hi All,
I need to pass a variable to perl script from bash script, where in perl i am using if condition. Here is the cmd what i am using in perl
FROM_DATE="06/05/2008"
TO_DATE="07/05/2008"
"perl -ne ' print if ( $_ >="$FROM_DATE" && $_ <= "$TO_DATE" ) ' filename"
filename has... (10 Replies)
How do I pass a bash variable to a javascript?
I've tried
#!/bin/bash
echo "Content-type: text/html"
echo ""
echo "<html>"
echo "<head>"
counter=0
echo '<script>
window.parent.document.forms.counter.value = "$counter";
</script>'
I have an iframe script which I am trying to pass a... (3 Replies)
I been trying to figure out how to use element of array as a replacement pattern. This works as I expected:
$ echo "one two three" | awk '{
gsub(/wo/,"_BEG_&_END_",$2);
print }'
one t_BEG_wo_END_ three
$ echo "one two three" | awk '{
tmp="foo";
gsub(/wo/,"_BEG_" tmp "_END_",$2);... (5 Replies)
Here is my code
#!/bin/bash
username=gnowicki
sed '$s/$/ $username/' < sshd_config 1 <> sshd_config
what this is supposed to do is take the name gnowicki and put it at the end of the last line of the sshd_config and it works except not using the variable, if I put the name "gnowicki" where... (2 Replies)
I'm trying to write a basic bash script that takes input you give (what directory, if any, what name, if any ....) and passes the information to find.
I'm trying to just create a string with all variables and then pass it to find. So far I have this extremely simple:
#!/bin/bash -f
... (2 Replies)
Hello,
I have searched but failed to find what exactly im looking for,
I need to eliminate first "." in a output so i can use something like the following
echo "./abc/20141127" | nawk '{gsub("^.","");print}'
what i want is to use gsub result later on, how could i achieve it?
Let say... (4 Replies)
Hi All,
I need to pass a variable from bash script to perl script and in the perl script i am using those variables in the sql query but its giving
error :
Use of uninitialized value $ENV{"COUNTRYCD"} in concatenation (.) or string at /GIS_ROOT/custom/tables/DBread_vendor.pl line 50.
Can ... (6 Replies)
I have input file
04000912|100:|||||]|101:||]|creDate:1451876825000|1441324800000:]|1444003200000:]|1446595200000:]|1449187200000:]|1451865600000:]
I have to get output as below
ID|Re_Date|Re_Value|Re_date
04000912|100|40.0|44
04000912|100|50.0|55
04000912|100|60.0|66... (4 Replies)
Hi Forum.
I'm trying to cleanup the following data elements (To remove any occurences of commas and any extra spaces) while preserving the <TAB> delimiter using awk gsub but I have not been successful.
Original Data:
4365 monte des source rue,, ,<TAB>trevost<TAB>QC
Desired Data:... (1 Reply)
Discussion started by: pchang
1 Replies
LEARN ABOUT PHP
print
PRINT(3) 1 PRINT(3)print - Output a stringSYNOPSIS
int print (string $arg)
DESCRIPTION
Outputs $arg.
print is not actually a real function (it is a language construct) so you are not required to use parentheses with its argument list.
PARAMETERS
o $arg
- The input data.
RETURN VALUES
Returns 1, always.
EXAMPLES
Example #1
print examples
<?php
print("Hello World");
print "print() also works without parentheses.";
print "This spans
multiple lines. The newlines will be
output as well";
print "This spans
multiple lines. The newlines will be
output as well.";
print "escaping characters is done "Like this".";
// You can use variables inside a print statement
$foo = "foobar";
$bar = "barbaz";
print "foo is $foo"; // foo is foobar
// You can also use arrays
$bar = array("value" => "foo");
print "this is {$bar['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
print 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just print variables
print $foo; // foobar
print <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon no extra whitespace!
END;
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO echo(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group PRINT(3)