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Shell Programming and Scripting
Bash shell script: Str(007) to int(7),increment it(8) & convert back to string(008)
Post 302578380 by drwatson_droid on Thursday 1st of December 2011 11:26:47 AM
12-01-2011
thanks a lot
---------- Post updated at 09:56 PM ---------- Previous update was at 09:49 PM ----------
Re: Bash shell script: Str(007) to int(7),increment it(
& convert back to string(00
thanks solved
---------- Post updated at 09:56 PM ---------- Previous update was at 09:49 PM ----------
Re: Bash shell script: Str(007) to int(7),increment it(
& convert back to string(00thanks solved
Quote:
newval=0
filename=search-build.txt
rexpression_sed='PRODUCT_VERSION=\"V:\([0-9]*\).\([0-9]*\).\([0-9]*\).Build\([0-9]*\)\"'
incrementnum=`grep -sn $rexpression_sed $filename | sed -e 's/'$rexpression_sed'/\1\t\2\t\3\t\4/g'| cut -f 3`
echo "Current Incremental number is: " $incrementnum
if [ $incrementnum ]
then
calcval=$(expr $incrementnum + 1)
#echo $calcval
if [ $calcval -le 9 ];
then
newval="00$calcval"
elif [ $calcval -le 99 ];
then
newval="0$calcval"
else
newval="$calcval"
fi
echo "New Incremental number is: " $newval
rexpression_rep_final='PRODUCT_VERSION="V:\1.\2.'$newval'.Build\4"'
#replace with new number
sed -i 's/'$rexpression_sed'/'$rexpression_rep_final'/' $filename
fi
filename=search-build.txt
rexpression_sed='PRODUCT_VERSION=\"V:\([0-9]*\).\([0-9]*\).\([0-9]*\).Build\([0-9]*\)\"'
incrementnum=`grep -sn $rexpression_sed $filename | sed -e 's/'$rexpression_sed'/\1\t\2\t\3\t\4/g'| cut -f 3`
echo "Current Incremental number is: " $incrementnum
if [ $incrementnum ]
then
calcval=$(expr $incrementnum + 1)
#echo $calcval
if [ $calcval -le 9 ];
then
newval="00$calcval"
elif [ $calcval -le 99 ];
then
newval="0$calcval"
else
newval="$calcval"
fi
echo "New Incremental number is: " $newval
rexpression_rep_final='PRODUCT_VERSION="V:\1.\2.'$newval'.Build\4"'
#replace with new number
sed -i 's/'$rexpression_sed'/'$rexpression_rep_final'/' $filename
fi
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