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Top Forums Shell Programming and Scripting grep option to print the first match of each member of a list? Post 302577593 by yifangt on Tuesday 29th of November 2011 11:46:24 AM
Old 11-29-2011
swapped the order of the two files!

Sorry!
After your last email I double checked the script and found out the mistake I made was the swapped order of the two files, which should be:
Code:
awk 'BEGIN { while(getline<"listfile") M[$1]=1 }; { if(M[$1]==1) { print; M[$1]=2 } }' datafile

Thanks a lot!
Yifang
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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