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Top Forums Shell Programming and Scripting Passing argument on find command Post 302577115 by ajithbe on Monday 28th of November 2011 08:30:13 AM
Old 11-28-2011
Passing argument on find command

Hi,
I'm trying to pass the variable in the find command like below


Code:
a=log.20111114
find /apps/file3_logs/env3/ -name '$a' -exec ls -lrt {} \;


but it's not working
thanks in advance.

Regards
Thelak

Last edited by zaxxon; 11-28-2011 at 09:46 AM.. Reason: code tags
 

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KNIFE-EXEC(1)							    Chef Manual 						     KNIFE-EXEC(1)

NAME
knife-exec - Run user scripts using the Chef API DSL SYNOPSIS
knife exec (options) -E, --exec CODE Provide a snippet of code to evaluate on the command line DESCRIPTION
knife exec runs arbitrary ruby scripts in a context similar to that of the shef(1) DSL. See the shef documentation for a description of the commands available. EXAMPLES
Make an API call against an arbitrary endpoint knife exec -E 'api.get("nodes/fluke.localdomain/cookbooks")' => list of cookbooks for the node fluke.localdomain Remove the role obsolete from all nodes knife exec -E 'nodes.transform(:all){|n| n.run_list.delete("role[obsolete]")}' Generate the expanded run list for hosts in the webserver role knife exec -E 'nodes.find(:roles => "webserver") {|n| n.expand!; n[:recipes]}' SEE ALSO
shef(1) AUTHOR
Chef was written by Adam Jacob adam@opscode.com with many contributions from the community. DOCUMENTATION
This manual page was written by Joshua Timberman joshua@opscode.com. Permission is granted to copy, distribute and / or modify this docu- ment under the terms of the Apache 2.0 License. CHEF
Knife is distributed with Chef. http://wiki.opscode.com/display/chef/Home Chef 10.12.0 June 2012 KNIFE-EXEC(1)
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