Here is a simplified example of my problem. Say I have the following 3 sub-directories;

./folder1
A.txt
A.sh

./folder2
B.txt

./folder3
C.txt
C.sh

I would like to list the directory names which contain both '.txt' & '.sh' type extensions. I have came up with the following code;

Code:

find . -type f \( -name "*.txt" -o -name "*.sh" \) -exec ls -l {} \; | sed 's/[^/]*$//'

This produces the following output;

./folder1/ (e.g ./folder1/A.txt)
./folder1/ (e.g ./folder1/A.sh)
./folder3/ (e.g ./folder3/C.txt)
./folder3/ (e.g ./folder3/C.sh)

This is a list of each directory for each instance of '.txt' and '.sh'. What I really want is only;

./folder1/
./folder3/

Would be great if this could all be done in the same line of code (find command). This is probably straight forward but I just cant seem to get it.

Thanks in advance.