11-10-2011
If you remove the virtual keyword then the function doesn't get put into the virtual function table. Therefore, I believe any calls to the function are bound to the function within the type's class. Since yahoo is using base, all calls it makes inside that class are bound to base's function. However, virtual functions are always bound to the vtable (unless you explicitly override it).
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LEARN ABOUT DEBIAN
ost_ipv6validator
ost::IPV6Validator(3) Library Functions Manual ost::IPV6Validator(3)
NAME
ost::IPV6Validator -
Classes derived from IPV6Address would require an specific validator to pass to the IPV6Address constructor.
SYNOPSIS
#include <address.h>
Inherited by ost::IPV6MulticastValidator.
Public Member Functions
IPV6Validator ()
Constructor.
virtual ~IPV6Validator ()
Keeps compilers happy.
virtual void operator() (const in6_addr address) const =0
Pure virtual application operator.
Detailed Description
Classes derived from IPV6Address would require an specific validator to pass to the IPV6Address constructor.
This is a base class for classes of function objects used by such derived classes.
Author:
Federico Montesino p5087@quintero.fie.us.es Abstract base class for derived inet addresses validators.
Constructor & Destructor Documentation
ost::IPV6Validator::IPV6Validator () [inline]
Constructor. Does not deal with any state.
virtual ost::IPV6Validator::~IPV6Validator () [inline], [virtual]
Keeps compilers happy.
Member Function Documentation
virtual void ost::IPV6Validator::operator() (const in6_addraddress) const [pure virtual]
Pure virtual application operator. Apply the validation algorithm specific to derived classes.
Implemented in ost::IPV6MulticastValidator.
Author
Generated automatically by Doxygen for GNU CommonC++ from the source code.
GNU CommonC++ Sat Jun 23 2012 ost::IPV6Validator(3)