(BASH) Using a loop variable to grep something in a file?
Hi,
I have a loop running until a variable L that is read previously in the full script. I'd like to grep some information in an input file at a line that contains the value of the loop parameter $i.
I've tried to use grep, but the problem is nothing is written in the FILE files. It seems grep cannot find "$i".
(I've tried to avoid awk to keep the sed etc I'm using after.)
Any idea?
Thanks in advance!
Code:
#!/bin/bash
L=5
INPUT=input
for i in $(eval echo {0..$L})
do
FILE=File$i.dat
test -e $FILE || touch $FILE
grep "#stuff 1 1 $i stuff_i_want_to_get" $INPUT | sed "y/(),/ /" | cut -d' ' -f6- >> $FILE
done
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Discussion started by: Adarshreddy01
8 Replies
LEARN ABOUT LINUX
xzgrep
XZGREP(1) XZ Utils XZGREP(1)NAME
xzgrep - search compressed files for a regular expression
SYNOPSIS
xzgrep [grep_options] [-e] pattern file...
xzegrep ...
xzfgrep ...
lzgrep ...
lzegrep ...
lzfgrep ...
DESCRIPTION
xzgrep invokes grep(1) on files which may be either uncompressed or compressed with xz(1), lzma(1), gzip(1), or bzip2(1). All options
specified are passed directly to grep(1).
If no file is specified, then standard input is decompressed if necessary and fed to grep(1). When reading from standard input, gzip(1)
and bzip2(1) compressed files are not supported.
If xzgrep is invoked as xzegrep or xzfgrep then egrep(1) or fgrep(1) is used instead of grep(1). The same applies to names lzgrep, lze-
grep, and lzfgrep, which are provided for backward compatibility with LZMA Utils.
ENVIRONMENT
GREP If the GREP environment variable is set, xzgrep uses it instead of grep(1), egrep(1), or fgrep(1).
SEE ALSO grep(1), xz(1), gzip(1), bzip2(1), zgrep(1)Tukaani 2010-09-27 XZGREP(1)