Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: how to get the variable in while loop outside of it?
Top Forums Shell Programming and Scripting how to get the variable in while loop outside of it? Post 302571225 by munish259272 on Sunday 6th of November 2011 11:07:04 PM
Old 11-07-2011
how to get the variable in while loop outside of it?
bash-3.00$ cat compare.sh
#NOTE : 1.Filename must not have space for the script to work.
# 2.Script wont work if symlinks are there instead of proper filenames.

Code:
#!/bin/bash
#set -x

#############################VERIFYING THE EXISTENCE OF DUPLICATE FILENAMES IN THE SUPPLIED FILENAMES ###############

if [[ $# -lt 1 ]];then
echo "Usage : `basename $0` filename" 1>&2
exit 2
fi
awk '{f=$9;
        for(i=10;i<=NF;i++)
           f=f" "$i;
           d[f]++;
     }
END{
        for(f in d)
                if(d[f] > 1)
                 printf("file %s occurs %d times\n",f,d[f]);
                                                    }' `basename $1`
echo -e  "Please remove the dupliacte entries,\
\nkeep the file with the latest timestamp and check again"

################################CHECKING SIZE,DATE,TIME,FILENAME WITH THE EXISTING FILES############################

status=0
cat $1 | awk '{print $(NF-4),"\t",$(NF-3),"\t",$(NF-2),"\t",$(NF-1),"\t",$(NF)}' | \
while read size mon day time filename; do
    if [[ ! -f "$filename" ]]; then
        echo "ERROR: no such file: $filename" >&2
        status=1
    else
        filesize=$(ls -lrt "$filename" | awk '{print $5}')
        if [[ "$size" != "$filesize" ]]; then
            echo "ERROR: size mismatch: $filename" >&2
            status=1
        else
           # filetime=$(ls -lrt "$filename" | awk '{print $6," ",$7," ",$8}')
                actual_mon=$(ls -lrt "$filename" | awk '{print $6}')
                actual_day=$(ls -lrt "$filename" | awk '{print $7}')
                actual_time=$(ls -lrt "$filename" | awk '{print $8}')
            if [[ "$mon $day $time" != "$actual_mon $actual_day $actual_time" ]]; then
                echo "ERROR: date mismatch: $filename" >&2
                status=1
            fi
        fi
    fi
done
echo $status
if [[ "$status" -eq 0 ]];then
echo -e "\t\n\nSuccess! All the files are found and their size and timestamp is also matching with the existing files."
else
echo -e "\t\n\nFailure! Non-matching files are found or file doesn't exist."
fi


The value of status always remains 0.
How do i get the changed value from inside the while loop


On the other hand :
Code:
bash-3.00$ cat scope.sh
#!/bin/bash
x=0
while [[ "$x" -lt 10 ]];do
x=$(($x+1))
done
echo $x

here, the value of x changes to 10

why is this deviation.

Please help me i need to access the changed value in the first script but i am unable to do it.
Last edited by Franklin52; 11-07-2011 at 06:03 AM.. Reason: Please use code tags for data and code samples, thank you
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

variable in a for loop

Hi... i am trying to ping my servers .The hostnames are present in a file .They are separated by spaces in the file . i am doing the following : a=1 for name in $(cat host2 |cut -d" " -f$a) do echo Pinging server $name ping -c5 $name a=$a+1 done It is... (3 Replies)
Discussion started by: sars
3 Replies

2. Shell Programming and Scripting

loop through variable

i have these data in a variable "$test" BUNGA TERATAI 3 5055 ITH 1 1 JADE TRADER 143W ITH 4 4 MOL SPLENDOR 0307A ITH 3 3 the red coloured are the ones that i want to take and compare what I need to do is to take out the red coloured and then compare to another variable, if same then... (0 Replies)
Discussion started by: finalight
0 Replies

3. Shell Programming and Scripting

For loop Variable

Hi, Is it possible to assign one variable to other. eg. v1="table1" v2="20000" I want table1 to assign 20000 table1=20000 Is there any way? Thanks (2 Replies)
Discussion started by: SushilM
2 Replies

4. Shell Programming and Scripting

Help with variable using loop

Hi I have webserver that I do read data from. Data are stored like this: Huston |1 Portland |2 Hazen |1 Minneapolis |4 Albany |1 Pittsburg |1 Albany |1 Huston |1 Portland|1 Hazen |2 Albany |2 Huston |1 Hazen |1 Script #!/bin/sh user="admin" (1 Reply)
Discussion started by: Jotne
1 Replies

5. Shell Programming and Scripting

For loop with one variable as the name of other

Hello all, I find it hard to explain what I need so I will post the code OVZINCLUDE="16810 16811 1689" PLUS_16810="test" PLUS_16811="test" for VPS in $OVZINCLUDE do echo "Dumping VPSes: $OVZINCLUDE " vzdump --compress --snapshot ${PLUS_$VPS} $VPS done ... (2 Replies)
Discussion started by: click
2 Replies

6. Shell Programming and Scripting

[SHELL: /bin/sh] For loop using variable variable names

Simple enough problem I think, I just can't seem to get it right. The below doesn't work as intended, it's just a function defined in a much larger script: CheckValues() { for field in \ Group_ID \ Group_Title \ Rule_ID \ Rule_Severity \ ... (2 Replies)
Discussion started by: Vryali
2 Replies

7. Shell Programming and Scripting

printing variable with variable suffix through loop

I have a group of variables myLINEcnt1 - myLINEcnt10. I'm trying to printout the values using a for loop. I am at the head banging stage since i'm sure it has to be a basic syntax issue that i can't figure out. For myIPgrp in 1 2 3 4 5 6 7 8 9 10; do here i want to output the value of... (4 Replies)
Discussion started by: oly_r
4 Replies

8. UNIX for Dummies Questions & Answers

Loop and variable not exactly variable: what's wrong

Hello guys, This truly is a newbie question. I'm trying to make a loop to execute simultaneous commands indefinitely while using variable. Here is how my mess looks like (this is just an example): #!/bin/bash IP=`shuf -n 1 IP.txt` # I figured this would be easier to select random lines... (4 Replies)
Discussion started by: bobylapointe
4 Replies

9. Shell Programming and Scripting

Array Variable being Assigned Values in Loop, But Gone when Loop Completes???

Hello All, Maybe I'm Missing something here but I have NOOO idea what the heck is going on with this....? I have a Variable that contains a PATTERN of what I'm considering "Illegal Characters". So what I'm doing is looping through a string containing some of these "Illegal Characters". Now... (5 Replies)
Discussion started by: mrm5102
5 Replies

10. Shell Programming and Scripting

[Solved] How to increment and add variable length numbers to a variable in a loop?

Hi All, I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Discussion started by: danish0909
5 Replies

LEARN ABOUT DEBIAN

syslogout

SYSLOGOUT(8)						      System Manager's Manual						      SYSLOGOUT(8)

NAME

       syslogout - modular centralized shell logout mechanism

DESCRIPTION

       syslogout is a generic approach to enable centralized shell logout actions for all users of a given system in a modular and centralized way
       mostly aimed at avoiding work for lazy sysadmins.  It has only been tested to work with the bash shell.

       It basically consists of the small /etc/syslogout shell script which invokes other small shell scripts having a .bash suffix which are con-
       tained  in  the	/etc/syslogout.d/ directory.  The system administrator can drop in any script he wants without any naming convention other
       than that the scripts need to have a .bash suffix to enable automagic sourcing by the /etc/syslogout script.

       For shell sessions, the contents of /etc/syslogout.d/" will be sourced by every user at logout if the following lines are  present  in  his
       $HOME/.bash_logout:

	   if [ -f /etc/syslogout ]; then
	       . /etc/syslogout
	   fi

       If  used  for X sessions it is advisable to include the former statement into the Xreset script of the X display manager instead to prevent
       that closing of an terminal emulator window yields unexpected results in your running X session if your X11 terminal emulator  is  using  a
       login  shell.   Be  sure  then to run it under the user-id of the X session's user.  See the example files in /usr/share/doc/syslogout/ for
       illustration.

       Users not wanting /etc/syslogout to be sourced for their environment can easily disable it's automatic mechanism.  It can  be  disabled	by
       simply creating an empty file called $HOME/.nosyslogout in the user's home directory using e.g. the touch(1) command.

       Any single configuration file in /etc/syslogout.d/ can simply be overridden by any user by creating a private $HOME/.syslogout.d/ directory
       which may contain a user's own version of any configuration file to be sourced instead of the system default.   It's  names  have  just	to
       match  exactly  the  system's  default /etc/syslogout.d/ configuration files.  Empty versions of these files contained in the $HOME/.syslo-
       gout.d/ directory automatically disable sourcing of the system wide version.

       Naturally, users can add and include their own private scripts to be automagically executed by /etc/syslogout at logout time.

OPTIONS

       There are no options other than those dictated by shell conventions.  Anything is defined within the configuration scripts themselves.

SEE ALSO

       The  README  files  and	configuration  examples  contained  in	/usr/share/doc/syslogout/  and	the  manual  page  for	bash(1),  xdm(1x),
       xdm.options(5), and wdm(1x).  Recommended further reading is everything related with shell programming.

       If  you need a similar mechanism for executing code at login time check out the related package sysprofile(8) which is a very close compan-
       ion to syslogout.

BUGS

       syslogout in its current form is mainly restricted to bash(1) syntax.  In fact it is actually  a rather embarrassing quick and  dirty  hack
       than  anything  else  -	but  it  works.   It  serves the practical need to enable a centralized bash configuration  until something better
       becomes available.  Your constructive criticism in making  this	into something better" is very welcome.  Before i forget to mention it: we
       take patches... ;-)

AUTHOR

       syslogout  was developed by Paul Seelig <pseelig@debian.org> specifically for the Debian GNU/Linux system.  Feel free to port it to and use
       it anywhere else under the conditions of either the GNU public license or the BSD license or both.  Better yet, please help to make it into
       something more worthwhile than it currently is.

																      SYSLOGOUT(8)
All times are GMT -4. The time now is 04:08 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy