ALTER TABLE $DBN.$TBN
ADD $COL $TYP COMPRESS ($VAL);
I need to cat the file and have it substitute all of the variables with their contents. cat MyFile does not work. The following works for the first line, but errors on the second line because of the paren:
Code:
$ while read L;do eval echo "$L";done<MyFile
ALTER TABLE MyDatabase.MyTable
ksh: syntax error: `(' unexpected
Any suggestions?
No, I cannot remove the parens as they are part of the SQL syntax.
Last edited by Franklin52; 11-03-2011 at 04:06 AM..
Reason: Please use code tags, thank you
Hey All,
I'm trying to clean up a variable using sed but It dosn't seem to work. I'm trying to find all the spaces and replace them with "\ " (a slash and a space). For Example "Hello World" should become "Hello\ World". But it does nothing. If I put it directly into the command line it works... (3 Replies)
Hi,
does anybody knows about wc -l, how to transform it inot a just number?
this script ALWAYS executes the command3!!, However, the value of BMU_RUNNING is 1
case $BMU_RUNNING in
*0) command1
;;
*1) command 2;;
*)command 3;;
esac
The... (3 Replies)
I have a question to do and it's somewhat confusing. It says, and I quote
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Hello,
i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem.
my var1 is a string constructed like this:
filename1 filerev1 filepath1
my var2 is another string constructed like this:
filename2 filerev2 filepath2
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I have a file with a single filename in it, which I want to assign to a BASH variable, so I've been trying:
c=$(head -1 somefile)
echo $c
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...
somecommand $c
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Hi ,
I have a variable as follows,
Temp=`cat ABC.txt | cut -c5-`
This will yeild a part of the date. say , 200912.
I would like to substitute this variable's value in a filename.
eg: File200912F.zip
when i say File$TempF.zip , it is not substituting.
Any help ?
Thanks in... (2 Replies)
For example I have variable like below
echo $OUTPUT
/some/path/`uname -n`
when I try to use the variable OUTPUT like below
cd $OUTPUT or cd ${OUTPUT}
I am getting bad substituion error message
$ cd $OUTPUT
ksh: cd: bad substitution
$ cd ${OUTPUT}
ksh: cd: bad substitution
... (1 Reply)
I have a huge script which is defining variables with full path of commands in the beginning of code and using those variables in the script.
For Example:
ECHO=/bin/echo
LS=/bin/ls
SED=/bin/sed
AWK=/bin/awk
UNAME=/bin/uname
PS=/bin/ps
DATE=/bin/date
GREP=/bin/grep
$ECHO "hello... (1 Reply)
I am trying to cat on a file located on remote server and assign it to remote variable.
I have both local and remote variables. Running below script from local. test.sh
J_NAME=XXX2
J_IP=XXX
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Thank you in advance for looking at this, I've scoured the internet and can't find the answer I'm looking for!! - I am new at bash script so please bare with me!!
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Discussion started by: paperbackwriter
3 Replies
LEARN ABOUT CENTOS
alter_group
ALTER GROUP(7) PostgreSQL 9.2.7 Documentation ALTER GROUP(7)NAME
ALTER_GROUP - change role name or membership
SYNOPSIS
ALTER GROUP group_name ADD USER user_name [, ... ]
ALTER GROUP group_name DROP USER user_name [, ... ]
ALTER GROUP group_name RENAME TO new_name
DESCRIPTION
ALTER GROUP changes the attributes of a user group. This is an obsolete command, though still accepted for backwards compatibility, because
groups (and users too) have been superseded by the more general concept of roles.
The first two variants add users to a group or remove them from a group. (Any role can play the part of either a "user" or a "group" for
this purpose.) These variants are effectively equivalent to granting or revoking membership in the role named as the "group"; so the
preferred way to do this is to use GRANT(7) or REVOKE(7).
The third variant changes the name of the group. This is exactly equivalent to renaming the role with ALTER ROLE (ALTER_ROLE(7)).
PARAMETERS
group_name
The name of the group (role) to modify.
user_name
Users (roles) that are to be added to or removed from the group. The users must already exist; ALTER GROUP does not create or drop
users.
new_name
The new name of the group.
EXAMPLES
Add users to a group:
ALTER GROUP staff ADD USER karl, john;
Remove a user from a group:
ALTER GROUP workers DROP USER beth;
COMPATIBILITY
There is no ALTER GROUP statement in the SQL standard.
SEE ALSO GRANT(7), REVOKE(7), ALTER ROLE (ALTER_ROLE(7))
PostgreSQL 9.2.7 2014-02-17 ALTER GROUP(7)
11-02-2011
cat file with variable substitution
