QUESTION: How can I cut out the date from just the first line and reformat it to 31-Jul-2007? I'll restate the question at the bottom again...
DESCRIPTION: I need to cut a date out of a file - an example of the date's format in the file is 2007-07-31. It's in the 5th field and is separated... (1 Reply)
I need to your help. I want write a script search for rows in file1 if exist in file2 it will print rows from file2 else it will print rows from file1 with out any duplicate
... (4 Replies)
My apache logs look like this...
PHP Warning: Invalid argument supplied for foreach() in /usr/local/apache2/htdocs/myfile.php
PHP Warning: Invalid argument supplied for foreach() in /usr/local/apache2/htdocs/myfile.php
PHP Warning: Invalid argument supplied for foreach() in... (1 Reply)
Hi,
sample datas are :
drwxr-xr-x 2 beewin abidev 96 Jun 13 2006 bwin
drwxrwxr-x 2 blsmg01 smg 96 Jun 13 2006 blsmg01
drwxr-xr-x 2 ccmdummy ccm_root 8192 Jun 13 2006 ccmdum
drwxr-xr-x 5 dipayan users 8192 Oct 29 09:05 dip
I want to cut the last field.
I use ls -ll | grep... (7 Replies)
Hi,
I have a shell script that reads a parameter file to set variables. I have an issue when the parameter I try to read contains whitespace.
e.g
File Contents
Code
The result is SUBJECT is set to
and I want subject set to
I've tried different variations but nothing seems to... (19 Replies)
I need to read in a file and output it without the comments or newlines.
The problem is that is not outputting it properly.
STUDENTSDETAILFILE="../data/studentDetails.txt"
for getlines in `sed '/#/d' $STUDENTSDETAILFILE`
do
STUDENTID=`echo $getlines | cut -d: -f1`
... (1 Reply)
Hi Gurus,
I have prepared a script to find the log file based on a date range defined in one of the environment files, archive the logs files and move them to a particular directory.
Below is the script:
. /home/.profile
. /home/.inf_env
logfile=$scripts_path/Logs/file_archive1.log... (17 Replies)
Hi, I am facing issue with cut and wc. here is the sample.
the data in file -
tail -1 05_19_BT_TBL_LOAD_20120524064242.bad|cut -c9-58
WatsSaver - AGGREGATED PLAN1581 CALLS FOR 2872.6
tail -1 05_19_BT_TBL_LOAD_20120524064242.bad|cut -c9-58|wc -c
51
tail -1... (12 Replies)
hi,
if I exectute "nohup time ls -1" I get the following output
$ nohup time ls -1
file_1
file_2
file_3
file_4
file_5
0.000u 0.001s 0:00.00 0.0% 0+0k 0+0io 0pf+0w
This is all OK.
But if I want to capture this whole output in to a text file I would want to use something like
... (1 Reply)
I have this filename "RBD_EXTRACT_a3468_d20131118.tar.gz" and I would like print out the "yyyymmdd" only. I use this command below, but if different command like cut or print....etc. Thanks
ls RBD_EXTRACT* | sed 's/.*\(........\).tar.gz$/\1/' > test.txt (9 Replies)
Discussion started by: dotran
9 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)