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Top Forums Programming Storing C++-struct in file - problem when adding new item in struct Post 302569725 by Corona688 on Tuesday 1st of November 2011 11:08:54 AM
Old 11-01-2011
You are mistaken. You cannot store "char *" in a file this way. You are storing pointers which, when you get them back, happen to point to some valid location in memory, but no mystical translation is happening -- a pointer is stored as 4 or 8 bytes, the data you wanted to store was never stored.

You must use fixed-size arrays like everything else.
 

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BINTIME_ADD(9)						   BSD Kernel Developer's Manual					    BINTIME_ADD(9)

NAME
bintime_add -- operations on ``bintime'' SYNOPSIS
#include <sys/time.h> vid bintime_add(struct bintime *bt, const struct bintime *bt2); void bintime_addx(struct bintime *bt, uint64_t x); void bintime_sub(struct bintime *bt, const struct bintime *bt2); void bintime2timespec(const struct bintime *bt, struct timespec *ts); void timespec2bintime(const struct timespec *ts, struct bintime *bt); void bintime2timeval(const struct bintime *bt, struct timeval *tv); void timeval2bintime(const struct timeval *tv, struct bintime *bt); DESCRIPTION
These functions are provided for convenience as part of the machine-independent timecounter(9) framework. All of them operate with the bintime structure. The function bintime_add() adds the time information stored in bt2 to bt. Conversely, bintime_sub() subtracts bt2 from bt. The bintime_addx() function stores the fraction of a second x to bt. Like the function names bespeak, bintime2timespec() converts the bintime structure to struct timespec and timespec2bintime() does the oppo- site. The functions bintime2timeval() and timeval2bintime() operate with struct timeval instead. The result is stored to the right-hand side. SEE ALSO
timeradd(3), timeval(3), bintime(9), timecounter(9) BSD
June 8, 2010 BSD
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