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Top Forums Shell Programming and Scripting Need help in running script on last day of month Post 302569365 by ahamed101 on Monday 31st of October 2011 04:47:50 AM
Old 10-31-2011
Try this...
Code:
#!/bin/bash
day=$(date +%d)
month=$(date +%m)
year=$(date +%Y)
run_or_not=$( awk -v day=$day -v month=$month -v year=$year 'BEGIN {
            if(month%2 && day == 30){ print "run" }else {
            if(month == 2){ leap=(0 == year % 4 && 0 != year % 100 || 0 == year % 400)
            if(leap && day == 29 ){ print "run" } else if(!leap && day == 28){ print "run"}
            } else if(day == 31){ print "run" } } }'  )
if [ "$run_or_not" == "run" ]
then
  echo "Execute your script!"
fi

--ahamed
This User Gave Thanks to ahamed101 For This Post:
 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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