10-21-2011
NO in fact I have 56 spaces at the end of the record. But the good news is the last two fields are fixed length which is not the case of all the preceding fields. Arg14= 4 cars Arg15=50 cars + 2 FS=56.
So I need to get from the end of $Arg13 to the EoL into a new variable and then I should be able to cut Arg14 and 15 from their positions.
Can you do a cut backwards from the end of line?
Any ideas welcome?
Zagga
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CUT(1) General Commands Manual CUT(1)
NAME
cut - select out columns of a file
SYNOPSIS
cut [ -b | -c] list [file...]
cut -f list [-d delim] [ -s]
OPTIONS
-b Cut specified bytes
-c Select out specific characters
-d Change the column delimiter to delim
-f Select out specific fields that are separated by the
-i Runs of delimiters count as one
-s Suppres lines with no delimiter characters, when used
EXAMPLES
cut -f 2 file # Extract field 2
cut -c 1-2,5 file # Extract character columns 1, 2, and 5
cut -c 1-5,7- file # Extract all columns except 6
DESCRIPTION
[file...]" delimiter character ( see delim)" with the -f option. Lines with no delimiters are passwd through untouched"
Cut extracts one or more fields or columns from a file and writes them on standard output. If the -f flag is used, the fields are sepa-
rated by a delimiter character, normally a tab, but can be changed using the -d flag. If the -c flag is used, specific columns can be
specified. The list can be comma or BLANK separated. The -f and -c flags are mutually exclusive. Note: The POSIX1003.2 standard requires
the option -b to cut out specific bytes in a file. It is intended for systems with multi byte characters (e.g. kanji), since MINIX uses
only one byte characters, this option is equivalent to -c. For the same reason, the option -n has no effect and is not listed in this man-
ual page.
SEE ALSO
sed(1), awk(9).
CUT(1)