Hi !
I have the following situation -
##First variable
variableA=JOB_A
##bunch of other variable
JOB_A_RESTART=cleanupJobA
JOB_B_RESTART=cleanupJobB
JOB_C_RESTART=cleanupJobC
now i need a script which would -
1. take the first variable
2. create a new variable name... (2 Replies)
Hello,
If anyone could help me out with this, it would be greatly appreciated. I am trying to dynamically create files and print to them.
Here is the code I have to so far. thanks.
if (n < 5000 )
{
# do nothing
}
else
{
n = 0;
filenum++;
# out = ("out" filenum);
}
... (1 Reply)
Hi All,
I want to create a shell script which dynamically create text files. i am using the following script
$i=1
while
do
cat > test_$i.txt
done
but while running the script it was stopping(the cursor not going to next step, i have to enter ctrl+c to make it stop). it is creating only... (2 Replies)
I have 3 variables with different information.. they look like this (row-wise aswell):
Variable1 =
Roland
Kalle
Dalius
Variable2 =
ake123
ler321
kaf434
Variable3 =
Richardsen
Sworden
Lokthar
How can I sort them by variable3 alphabetical and add them into the same output so... (0 Replies)
i'm trying to write a script that has 2 variables, and uses the 1st variable as a number and the 2nd a name to create directories. so if you typed in ./myscript 5 week, it would create 5 directories named week1 - week5. whenever i run this, i get an error message saying week5 already exists, so i... (3 Replies)
Hi,
For one of the project which i am working on i need to write a cpp code such that it will create the structure dynamically instead of reading it from header file.
For example we have a program which is reading a binary file according to the structure mentioned in header file.
But we... (0 Replies)
I am writing some scripts using bash and am wondering if there is a better way to perform the following set of formatting variables.
s1=" "
s2=" "
s3=" "
s4=" "
s5=" "
s6=" "
s7=" "
s8=" "
frmt_titl="${bYl}%s${nClor}\n"
frmt1_titl="${s1}$frmt_titl"... (10 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Here is what I am supposed to do, word for word from my assignment page:
1. Create/modify and print a... (2 Replies)
Not sure how to do the following, but any help would be appreciated.
Has to be done using C shell (sorry about that).
I have about 300 files that I need this done for, but I am only going to give one example. I will just need to know how to execute your solution through some type of loop to get... (2 Replies)
Hi all,
I have a PLSQL script which has a IN list where it takes some ids as input. For example
SELECT * FROM EMPLOYEE WHERE EMPLOYEE_ID IN (comma separated list )
I want to run this quest inside a shell script but I would like to prepare the IN list dynamically where the employee ids... (1 Reply)
Discussion started by: LoneRanger
1 Replies
LEARN ABOUT PLAN9
zipgrep
ZIPGREP(1) General Commands Manual ZIPGREP(1)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1), zip(1), funzip(1), zipcloak(1), zipinfo(1), zipnote(1), zipsplit(1)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 20 April 2009 ZIPGREP(1)